python regex grouping

Question

Given string s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'

I would like to get this output: (C /something_3),/,(D /something_4)(D /something_5)

I keep matching the whole string s, instead of getting above substring.

I am using re.search(r'(\(C.*\)),/,(\(D.*\))+')

Any help is appreciated...

Chris Morgan · Accepted Answer · 2010-11-19 02:19:25Z

4

You're just about there - re.search(r'(\(C.*\)),/,(\(D.*\))+', s).group() will get you what you want.

>>> import re
>>> s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'
>>> re.search(r'(\(C.*\)),/,(\(D.*\))+', s).group()
'(C /something_3),/,(D /something_4)(D /something_5)'

Are you wanting to further split that in groups?

answered Nov 19, 2010 at 2:19

Chris Morgan

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Zooba · Accepted Answer · 2010-11-19 02:20:55Z

1

Using Python 2.7, I get the exact result you're after:

import re
s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'
m = re.search(r'(\(C.*\)),/,(\(D.*\))+', s)

s[m.start():m.end()] == '(C /something_3),/,(D /something_4)(D /something_5)'

answered Nov 19, 2010 at 2:20

Zooba

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