Regex, separate by comma, javascript

Question

My string:

AA,$,DESCRIPTION(Sink, clinical),$

Wanted matches:

AA
$
DESCRIPTION(Sink, clinical)
$

My regex sofar:

\+d|[\w$:0-9`<>=&;?\|\!\#\+\%\-\s\*\(\)\.ÅÄÖåäö]+

This gives

AA
$
DESCRIPTION(Sink
clinical)

I want to keep matches between ()

https://regex101.com/r/MqFUmk/3

Please verify the string in the example! The desired output makes no sense! — ibrahim mahrir
– ibrahim mahrir, Commented Feb 15, 2017 at 20:29
How many levels of parenthesis there could be? Could the string be like this: $, gg(ee(), yy), ee? — ibrahim mahrir
– ibrahim mahrir, Commented Feb 15, 2017 at 20:34
Maybe this with parenthesis instead could help stackoverflow.com/a/18147076/340760 — BrunoLM
– BrunoLM, Commented Feb 15, 2017 at 20:37
@BrunoLM That's a nice link, though I'd like to point out that the delimiters are commas, and the secondary delimiters are quotes (which OP could replace with parentheses... maybe) — Sunny Patel
– Sunny Patel, Commented Feb 15, 2017 at 20:53

Community · Accepted Answer · 2017-05-23 12:17:23Z

1

Here's my attempt at the regex

\+d|[\w$:0-9`<>=&;?\|\!\#\+\%\-\s\*\.ÅÄÖåäö]+(\(.+\))?

I removed the parentheses from within the [ ] characters, and allowed capture elsewhere. It seems to satisfy the regex101 link you posted.

Depending on how arbitrary your input is, this regex might not be suitable for more complex strings.

Alternatively, here's an answer which could be more robust than mine, but may only work in Ruby.

((?>[^,(]+|(\((?>[^()]+|\g<-1>)*\)))+)

edited May 23, 2017 at 12:17

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answered Feb 15, 2017 at 20:36

Adam

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1 Comment

Antony Over a year ago

Problem is if you add another ending parenthesis, it matches from the first parenthesis to the last one. I would suggest replacing the capture group with ($.+?$)?, making the inner parenthesis match lazy. In this case, the problems becomes if you have inner parenthesis such as (a(b)c), which would not be matched correctly.

nibnut · Accepted Answer · 2017-02-15 20:45:29Z

1

That one seems to work for me?

([^,\(\)]*(?:\([^\(\)]*\))?[^,\(\)]*)(?:,|$)

https://regex101.com/r/hLyJm5/2

Hope this helps!

answered Feb 15, 2017 at 20:45

nibnut

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Comments

Sunny Patel · Accepted Answer · 2017-02-15 21:30:39Z

1

Personally, I would first replace all commas within parentheses () with a character that will never occur (in my case I used @ since I don't see it within your inclusions) and then I would split them by commas to keep it sweet and simple.

myStr = "AA,$,DESCRIPTION(Sink, clinical),$";            //Initial string
myStr = myStr.replace(/(\([^,]+),([^\)]+\))/g, "$1@$2"); //Replace , within parentheses with @
myArr = myStr.split(',').map(function(s) { return s.replace('@', ','); }); //Split string on ,
//myArr -> ["AA","$","DESCRIPTION(Sink, clinical)","$"]

optionally, if you're using ES6, you can change that last line to:

myArr = myStr.split(',').map(s => s.replace('@', ','));  //Yay Arrow Functions!

Note: If you have nested parentheses, this answer will need a modification

edited Feb 15, 2017 at 21:30

answered Feb 15, 2017 at 20:47

Sunny Patel

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Comments

Álvaro Touzón · Accepted Answer · 2017-02-15 20:57:16Z

0

At last take an aproximation of what you need:

\w+(?:\(.*\))|\w+|\$

https://regex101.com/r/MqFUmk/4

answered Feb 15, 2017 at 20:57

Álvaro Touzón

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3 Comments

Joe Over a year ago

Nice and short. Spaces are not included though.

Álvaro Touzón Over a year ago

@PerStröm not includes, you dont need it?

Álvaro Touzón Over a year ago

[a-z\$A-Z]+(?:(.*))|[a-z\$A-Z]+ i think is more efficient

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