PHP: help with array structure

Question

My last question helped me get data from a form into an array. The array is fairly different in structure to anything I've used before. I have multiple records with a textbox and checkbox each. Here is the form data:

array(4) { 
["product"]=> array(4) { 
    [0]=> string(5) "Dummy" 
    [1]=> string(7) "Dummy 2" 
    [2]=> string(7) "Dummy 3" 
    [3]=> string(7) "Dummy 4" 
} 
["tags"]=> array(4) { 
    [0]=> string(25) "#enter, #product, #hastag" 
    [1]=> string(0) "" 
    [2]=> string(25) "#enter, #product, #hastag" 
    [3]=> string(25) "#enter, #product, #hastag" 
} 
["chk"]=> array(2) { 
    [0]=> string(2) "on" 
    [2]=> string(2) "on" 
} 
["submit"]=> string(5) "tweet" 

}

I want to get the data from this array into a form such as (only if chk = "on"):

tweet[0]["product"] = "dummy"
tweet[0]["tag"] = "hash tag list here"

tweet[1]["product"] = "dummy3"
tweet[1]["tag"] = "hash tag list here"

Any help most appreciated! :)

By adjusting your HTML you can get the desired $_POST format you're looking for... see my below answer — Ben
– Ben, Commented Nov 19, 2010 at 15:07

Jim · Accepted Answer · 2010-11-19 15:23:39Z

4

First I'd recommend using 1 instead of on. You should try to use numerical values whenever possible as they require less processing. I think you need to readjust your HTML, so you don't do any processing on the PHP side at all...

<input type="checkbox" name="tweet[(YOUR_TWEET_ID)][product]" value="PRODUCT_NAME"/>
<input type="text" name="tweet[(YOUR_TWEET_ID)][tags]" value=""/>

This will cause the form to $_POST exactly how you want it without any additional code.

update

foreach ($_POST['tweet'] as $tweetId => $value) {
   //again, it'd be a good idea to use a numerical value here
   if (strlen($value['product']) > 0) {
      //this tweet was checked, lets do with it what we need

      //here's how you'd get the tags
      echo $_POST['tweet'][$tweetId]['tags'];
   }
}

edited Nov 19, 2010 at 15:23

Jim

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answered Nov 19, 2010 at 15:07

Ben

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2 Comments

Tyler Carter Over a year ago

If you don't click the checkbox, the tags will still be there. I don't think that is suppose to happen.

Ben Over a year ago

I updated it to show how you'd utilize this code on the PHP side

Tyler Carter · Accepted Answer · 2010-11-19 15:10:39Z

2

$finalArray = array();
foreach($array['product'] as $key => $name){
    if(!empty($array['chk'][$key])){
        $finalArray[] = array(
            "product" => $name,
            "tag" => $array['tags'][$key]);
    };
}

edited Nov 19, 2010 at 15:10

answered Nov 19, 2010 at 15:05

Tyler Carter

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1 Comment

Jim Over a year ago

Like the array structure setup, +1.

Jim · Accepted Answer · 2010-11-19 15:05:01Z

1

Pretty simple:

$i=0;
foreach ($array['chk'] as $key => $val) {
     if ($val == "on") {
         $new_array[$i]['product'] = $array['product'][$key]; 
         $new_array[$i++]['tags'] = $array['tags'][$key];
     }
}

print_r($new_array);

Should do it, there are other ways, this is just one of them.

answered Nov 19, 2010 at 15:05

Jim

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5 Comments

Jim Over a year ago

@Felix Why not? It only iterates on the second one, and since it is $i++ it will only iterate after it prints what $i was.

Tyler Carter Over a year ago

@Brad the $i++ is confusing when used like that. It would probably be better to just increment it after for clarity, or just use the [] with an entire array (see my answer).

Jim Over a year ago

@Chacha102, I can understand that, however, it is not incorrect. But thanks for elaborating, appreciate it.

Ben Over a year ago

There's no point in processing any of this in PHP, it can be done on the HTML level, see my below answer..... I like $i++ being part of the loop like that, though it does take away from readability cause it'd be easy to overlook

Felix Kling Over a year ago

Sorry Brad, my mistake, you are right, $i is evaluated before it gets incremented... stupid me.

Mikhail · Accepted Answer · 2010-11-19 15:05:29Z

1

foreach ($records['chk'] as $id => $temp) {
  $tweet[$id]['product'] = $records['product'][$id];
  $tweet[$id]['tag'] = $records['tags'][$id];
}

answered Nov 19, 2010 at 15:05

Mikhail

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