Writing Python text file

Question

I'm trying to make script that generates 26 text files named a.txt, b.txt, and so on up to z.txt. Each file should contain a letter reflecting its filename. So, a.txt will contain letter a, b.txt will contain letter b and so on.

How I need to change this code that it generates .txt files? Now the script is almost correct but it doesn't make .txt files. I'm using Python 3.5. Here is my code:

import string
alphabet= string.ascii_lowercase
for letter in alphabet:
    with open(letter,'w') as file:
        file.write(letter)

MD. Khairul Basar · Accepted Answer · 2017-02-18 13:45:04Z

1

you need to do this-

import string
alphabet= string.ascii_lowercase
for letter in alphabet:
    with open(letter+".txt",'w') as file:
        file.write(letter)

answered Feb 18, 2017 at 13:45

MD. Khairul Basar

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Comments

mhawke · Accepted Answer · 2017-02-18 13:58:31Z

1

Construct the file name using string formatting. str.format() is the preferred way to perform string formatting:

import string

for letter in string.ascii_lowercase:
    with open('{}.txt'.format(letter), 'w') as f:
        f.write(letter)

N.B. Although this is not a problem in Python 3 you should try to avoid using the name file as a variable, it shadows the Python 2 builtin file object, and potentially makes your code less portable.

edited Feb 18, 2017 at 13:58

answered Feb 18, 2017 at 13:52

mhawke

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Comments

Max Nguyen · Accepted Answer · 2021-09-19 02:35:24Z

0

for i in range(0,26):
    alphabetLeter = chr(65+i)
    with open(f"{alphabetLeter}.txt", 'w') as fio:
        print(f"{alphabetLeter}.txt")

answered Sep 19, 2021 at 2:35

Max Nguyen

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