Is it possible to handle R.array.string-array-name through a string variable in android studio? [duplicate]

Question

I have strings.xml file like below:

<string-array name="planet">
    <item>Earth</item>
    <item>Mars</item>
    <item>Jupiter</item>
</string-array>

My activity_main.xml code segment for my spinner:

<Spinner
   android:id="@+id/spinner"
   android:layout_width="match_parent"
   android:layout_height="wrap_content"/>

My MainActivity.java code segment:

    Spinner spinner = (Spinner) findViewById(R.id.spinner);
    ArrayAdapter adapter = ArrayAdapter.createFromResource(this, R.array.planet, android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(this);

Now I want to do this code like below:

    Spinner spinner = (Spinner) findViewById(R.id.spinner);
    String arrayName = "planet";
    ArrayAdapter adapter = ArrayAdapter.createFromResource(this, R.array.arrayName, android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(this);

May I get the help that if it is possible then how to do this.

Chetan Joshi · Accepted Answer · 2017-03-01 06:54:34Z

2

You can get Integer Id of String Array from string.xml like below Code .

String arrayName = "planet";
int arrayName_ID= getResources().getIdentifier(arrayName , "array",this.getPackageName()); 
// You had used "arrayName"
String[] items = getResources().getStringArray(arrayName_ID);

answered Mar 1, 2017 at 6:54

Chetan Joshi

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Elias Fazel · Accepted Answer · 2017-03-01 06:50:23Z

1

String value = getResources().getStringArray(R.id.value_array)[selectedIndex];

and you get all String[] without specifying index.

answered Mar 1, 2017 at 6:50

Elias Fazel

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Comments

Chirag.T · Accepted Answer · 2017-03-01 06:50:50Z

0

You can use string array like

 ArrayList<String> string_array = new ArrayList<>(Arrays.asList(getResources().getStringArray(R.array.string_array_name)));

ArrayAdapter adapter = new ArrayAdapter(this, android.R.layout.simple_spinner_dropdown_item,string_array);

answered Mar 1, 2017 at 6:50

Chirag.T

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