How can I read a text file into a string variable and strip newlines?

In Python 3.5 or later, using pathlib you can copy text file contents into a variable and close the file in one line:

from pathlib import Path
txt = Path('data.txt').read_text()

and then you can use str.replace to remove the newlines:

txt = txt.replace('\n', '')

You can read from a file in one line:

str = open('very_Important.txt', 'r').read()

Please note that this does not close the file explicitly.

CPython will close the file when it exits as part of the garbage collection.

But other Python implementations won’t. To write portable code, it is better to use with or close the file explicitly. Short is not always better. See Is explicitly closing files important?

To join all lines into a string and remove new lines, I normally use:

with open('t.txt') as f:
  s = " ".join([l.rstrip("\n") for l in f]) 

Use:

with open("data.txt") as myfile:
    data = "".join(line.rstrip() for line in myfile)

join() will join a list of strings, and rstrip() without any arguments will trim whitespace, including newlines, from the end of strings.

There is also splitlines():

with open ("data.txt", "r") as myfile:
    data = myfile.read().splitlines()

Variable data is now a list that looks like this when printed:

['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']

Note there aren't any newlines (\n).

At that point, it sounds like you want to print back the lines to console, which you can achieve with a for loop:

for line in data:
    print(line)

This can be done using the read() method:

text_as_string = open('Your_Text_File.txt', 'r').read()

Or as the default mode itself is 'r' (read) so simply use,

text_as_string = open('Your_Text_File.txt').read()

It's hard to tell exactly what you're after, but something like this should get you started:

with open ("data.txt", "r") as myfile:
    data = ' '.join([line.replace('\n', '') for line in myfile.readlines()])

I have fiddled around with this for a while and have prefer to use use read in combination with rstrip. Without rstrip("\n"), Python adds a newline to the end of the string, which in most cases is not very useful.

with open("myfile.txt") as f:
    file_content = f.read().rstrip("\n")
    print(file_content)

Here are four codes for you to choose one:

with open("my_text_file.txt", "r") as file:
    data = file.read().replace("\n", "")

or

with open("my_text_file.txt", "r") as file:
    data = "".join(file.read().split("\n"))

or

with open("my_text_file.txt", "r") as file:
    data = "".join(file.read().splitlines())

or

with open("my_text_file.txt", "r") as file:
    data = "".join([line for line in file])

f = open('data.txt','r')
string = ""
while 1:
    line = f.readline()
    if not line:break
    string += line

f.close()


print(string)

You can compress this into one into two lines of code!

content = open('filepath', 'r').read().replace('\n', ' ')
print(content)

If your file reads:

hello how are you?
who are you?
blank blank

Python output

hello how are you? who are you? blank blank

You can also strip each line and concatenate into a final string.

myfile = open("data.txt","r")
data = ""
lines = myfile.readlines()
for line in lines:
    data = data + line.strip();

This would also work out just fine.

Python 3: See List Comprehensions for the square bracket syntax.

 with open('data.txt') as f:
     lines = [ line.rstrip('\n') for line in f ]

This is a one line, copy-pasteable solution that also closes the file object:

_ = open('data.txt', 'r'); data = _.read(); _.close()

Oneliner:

• List: "".join([line.rstrip('\n') for line in open('file.txt')])

• Generator: "".join((line.rstrip('\n') for line in open('file.txt')))

List is faster than generator but heavier on memory. Generators are slower than lists and is lighter for memory like iterating over lines. In case of "".join(), I think both should work well. .join() function should be removed to get list or generator respectively.

• Note: close() / closing of file descriptor probably not needed

Use:

from pathlib import Path
line_lst = Path("to/the/file.txt").read_text().splitlines()

It is the best way to get all the lines of a file. The '\n' are already stripped by the splitlines() (which smartly recognize win/mac/unix lines types).

But if nonetheless you want to strip each lines:

line_lst = [line.strip() for line in txt = Path("to/the/file.txt").read_text().splitlines()]

strip() was just a useful exemple, but you can process your line as you please.

At the end, do you just want concatenated text?

txt = ''.join(Path("to/the/file.txt").read_text().splitlines())

Try this:

x = "yourfilename.txt"
y = open(x, 'r').read()

print(y)

To remove line breaks using Python you can use replace function of a string.

This example removes all 3 types of line breaks:

my_string = open('lala.json').read()
print(my_string)

my_string = my_string.replace("\r","").replace("\n","")
print(my_string)

Example file is:

{
  "lala": "lulu",
  "foo": "bar"
}

You can try it using this replay scenario:

https://repl.it/repls/AnnualJointHardware

I don't feel that anyone addressed the [ ] part of your question. When you read each line into your variable, because there were multiple lines before you replaced the \n with '' you ended up creating a list. If you have a variable of x and print it out just by

x

or print(x)

or str(x)

You will see the entire list with the brackets. If you call each element of the (array of sorts)

x[0] then it omits the brackets. If you use the str() function you will see just the data and not the '' either. str(x[0])

A regular expression works too:

import re
with open("depression.txt") as f:
     l = re.split(' ', re.sub('\n',' ', f.read()))[:-1]

print (l)

Output:

['I', 'feel', 'empty', 'and', 'dead', 'inside']

You could try this. I use this in my programs.

Data = open('data.txt', 'r')
data = Data.readlines()
for i in range(len(data)):
    data[i] = data[i].strip() + ' '
data = ''.join(data).strip()

This works: Change your file to:

LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE

Then:

file = open("file.txt")
line = file.read()
words = line.split()

This creates a list named words that equals:

['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']

That got rid of the "\n". To answer the part about the brackets getting in your way, just do this:

for word in words: # Assuming words is the list above
    print word # Prints each word in file on a different line

Or:

print words[0] + ",", words[1] # Note that the "+" symbol indicates no spaces
#The comma not in parentheses indicates a space

This returns:

LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN, GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE

with open('data.txt', 'r') as file:
    data = [line.strip('\n') for line in file.readlines()]
    data = ''.join(data)

file = open("myfile.txt", "r")
lines = file.readlines()
str = ''                                     #string declaration

for i in range(len(lines)):
    str += lines[i].rstrip('\n') + ' '

print str

Use:

with open(player_name, 'r') as myfile:
    data = myfile.readline()
    list = data.split(" ")
    word = list[0]

This code will help you to read the first line and then using the list and split option, you can convert the first line word separated by space to be stored in a list.

then you can easily access any word, or even store it in a string.

You can also do the same thing with using a for loop.