PHP script error when value is zero

Question

I not understand little bit. Simple switch statement not working correctly with zero value (=0):

//$result = $sql->fetchColumn(); 
$result = 1;
      switch ($result) {    
          case $result <= 2 :
              throw new Exception('Error!');
              break;
                        }

Problem is when $result = 0 then output should be 'error' but in this case script passing this validation. Weird question but i can't find a problem.

This is just a fragment of the code. I need to find out why that's happens — Klapsius
– Klapsius, Commented Mar 1, 2017 at 12:23
You haven't understand how switch statement works. You can't execute a "greater than... less than" etc. in a switch statement. You can only do a case for a specific number. us2.php.net/manual/en/control-structures.switch.php — Twinfriends
– Twinfriends, Commented Mar 1, 2017 at 12:25
I've posted an answer that shows you how you can do it with a switch-statement. :) Hope you'll find your solution. If you need more help, feel free to ask. — Twinfriends
– Twinfriends, Commented Mar 1, 2017 at 12:28

Twinfriends · Accepted Answer · 2017-03-01 12:27:45Z

1

You can write it like that:

<?php
switch ($i) {
case 0:
case 1:
case 2:
    throw new Exception('Error!');
    break;
case 3:
    echo "i is 3 or higher.";
}
?>

As I said in my comment above, you can't use "grater than" "less than" etc. in a switch-statement. As other said, if you want to make use of them, use a simple IF statement.

answered Mar 1, 2017 at 12:27

Twinfriends

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Андрей Танечник · Accepted Answer · 2017-03-01 13:11:28Z

0

this code

switch ($result) {    
      case $result <= 2 :

is equivalent

if($result == ($result <= 2))

and when

$result=0

we have

( 0 == true )

after type conversion

false === true

and this is false as expected

edited Mar 1, 2017 at 13:11

answered Mar 1, 2017 at 12:38

Андрей Танечник

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