Bash/shell code to run command on a list file of variables

Question

so for starters i have the following, main process im running

for fname in (filename); do  
  ./$comma "$fname" (var1) (var2)  
  mv "$fname" "${fname}.fin"  
done

then i have a listfile of names looking like:

filename|var1|var2   
file1|9|1  
file2|8|3

etc...

would like to set it up where - when the master script goes to run the ./$comma script it reads from the listfile and populate the fname, var1, and var2 (per piped order) - right now i have a lot of repeated chunks of script like the above and would like to consolidate or clean it up for sure. Any help is appreciated - doesnt necessarily have to be a for;do loop - just as long as the script is ran on the right file with right args and gets renamed.

Thank you for this link - definitely helpful moving forward! — Jazzkatt
– Jazzkatt, Commented Mar 2, 2017 at 18:11

chepner · Accepted Answer · 2017-03-02 17:43:43Z

2

The for loop you show isn't syntactically correct. You want a while loop, though, that uses the read command.

while IFS="|" read -r fname var1 var2; do
  ./"$comma" "$fname" "$var1" "$var2"
  mv "$fname" "$fname.fin"
done < filenames.txt

answered Mar 2, 2017 at 17:43

chepner

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2 Comments

Jazzkatt Over a year ago

thank you so much, I do understand it wasnt syntactically correct for a reading of a file it was more a quick fix that turned into a frankenstein of a script.

Jazzkatt Over a year ago

I do want to ask - will this run always for every line in the filenames.txt? or will it "skip" those files that are not present when its being ran? cd "$ftf"

while IFS="|" read -r fname var1 var2; do     echo " Processing Comma MFIX: $fname" >> "$logfile"     ./"$comma" "$fname" "$var1" "$var2"     mv "$fname" "$fname.fin"   done < comma_strlst.txt

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