How to split Strings in java

Question

I have two types of Strings. One is "abcdEfgh" and "abcd efgh". That means first String is having upper case letter in between and second string is having white space. So now how do I check these two pattern string in java and make two strings.

String givenString;

if (givenString.equals("abcdEfgh")) {
   String str1 = abcd;
   String str2 = Efgh;
} else (givenString.equals("abcd efgh") {
   String str1 = abcd;
   String str2 = efgh;
}

Please provide the solution Thanks

String class has a split method. givenString.split(" "); for the white space example. — Jack Flamp
– Jack Flamp, Commented Mar 3, 2017 at 9:29
And for the uppercase example, stackoverflow.com/questions/3752636/… — BackSlash
– BackSlash, Commented Mar 3, 2017 at 9:30
Possible duplicate of Java: Split string when an uppercase letter is found — R. Oosterholt
– R. Oosterholt, Commented Mar 3, 2017 at 9:32
it is not a duplicate, as the question is about both cases (capital or white space delimiter), not one of them. — vefthym
– vefthym, Commented Mar 3, 2017 at 9:38
Could it be mixed "abcdEfgh rest"? Are there always extactly two parts to find? — wumpz
– wumpz, Commented Mar 3, 2017 at 9:59

vefthym · Accepted Answer · 2017-03-03 09:49:28Z

5

You can split using regex \\s|(?=[A-Z])

\\s is to deal with case of whitespace.
(?=[A-Z])is positive lookahead. It finds capital letter but keeps the delimiter while splitting.

.

String givenString;
String split[] = givenString.split("\\s|(?=[A-Z])");
String str1 = split[0];
String str2 = split[1];

for both cases

Test case 1

//case 1
givenString = "abcdEfgh";
str1 = abcd
str2 = Efgh

Test case 2

//case 2
givenString = "abcd efgh";
str1 = abcd
str2 = efgh

edited Mar 3, 2017 at 9:49

vefthym

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answered Mar 3, 2017 at 9:33

Raman Sahasi

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2 Comments

Pratibha Patil Over a year ago

@RamanSahasi Thanks for your ans. I am getting , str1=null and str2=abcd in the Test case 1

Raman Sahasi Over a year ago

@PratibhaPatil I've compiled and tested this code. Please take a look at this online version of my test cases.

Community · Accepted Answer · 2017-05-23 12:17:08Z

2

You need to combine the two conditions using the OR operator |. You've already figured out split by space is simply " ". The uppercase example is answered by Java: Split string when an uppercase letter is found

Example

String one = "abcdEfgh";
String two = "abcd efgh";

System.out.println(Arrays.toString(one.split(" |(?=\\p{Upper})")));
System.out.println(Arrays.toString(two.split(" |(?=\\p{Upper})")));

Output

[abcd, Efgh]
[abcd, efgh]

edited May 23, 2017 at 12:17

CommunityBot

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answered Mar 3, 2017 at 9:33

Adam

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2 Comments

Pratibha Patil Over a year ago

Thanks@Adam, both for upper case and white space same pattern ?

Adam Over a year ago

@PratibhaPatil Yep, as my example shows the same pattern can be used

ΦXocę 웃 Пepeúpa ツ · Accepted Answer · 2017-03-03 09:35:10Z

0

Keep it simple, search for space in givenString instead of case sensitive matchs

if(givenString.indexOf(" ") != -1){
    System.out.println( "The string has spaces");
}else{
    System.out.println( "The string has NO spaces");
}

answered Mar 3, 2017 at 9:35

ΦXocę 웃 Пepeúpa ツ

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