Regex for website or url validation [duplicate]

Question

I know this is so common question & there are so many answers for this, but my problem is different, I want to accept the URL with all below formats:

http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com

// & much more ...

So here idea is, I am allowing the user to enter there website & another user can just click on the saved website & go to users website. So here it's not a good idea to restrict the user to input proper URL, they can enter any of the above formats. Here is the regex I am using right now, but that only checks if URL starts from proper protocol:

^(ftp|http|https):\/\/[^ "]+$

Do you want validation for protocol or domain address?, If it's for protocol, check for default browser protocol if not specified, accordingly do validation. — Satishakumar Awati
– Satishakumar Awati, Commented Mar 6, 2017 at 6:30
Actually both, user can enter with protocol or only domain but not just any random string like, it should match those given criteria I have entered in question — Dheeraj Agrawal
– Dheeraj Agrawal, Commented Mar 6, 2017 at 6:32
so with proper protocol, if the url contains "sample.com" it should pass, is that what you mean ? — Mustofa Rizwan
– Mustofa Rizwan, Commented Mar 6, 2017 at 6:50
@Rizwan, Yes thats one of the best and easiest way to handle above validation. — Satishakumar Awati
– Satishakumar Awati, Commented Mar 6, 2017 at 6:56
@RizwanM.Tuman also its possible that there will be no protocol, so that should pass as well if there is no protocol I will handle it myself, why to ask user to enter it, some users even don't know HTTP or HTTPS — Dheeraj Agrawal
– Dheeraj Agrawal, Commented Mar 6, 2017 at 7:24

Sagar V · Accepted Answer · 2017-03-06 07:51:57Z

57

Use the regex ^((https?|ftp|smtp):\/\/)?(www.)?[a-z0-9]+\.[a-z]+(\/[a-zA-Z0-9#]+\/?)*$

This is a basic one I build just now. A google search can give you more.

Here

^ Should start with
((https?|ftp|smtp)://)? may or maynot contain any of these protocols
(www.)? may or may not have www.
[a-z0-9]+(.[a-z]+) url and domain and also subdomain if any upto 2 levels
(/[a-zA-Z0-9#]+/?)*/? can contain path to files but not necessary. last may contain a /
$ should end there

var a=["http://www.sample.com","https://www.sample.com/","https://www.sample.com#","http://www.sample.com/xyz","http://www.sample.com/#xyz","www.sample.com","www.sample.com/xyz/#/xyz","sample.com","sample.com?name=foo","http://www.sample.com#xyz","http://www.sample.c"];
var re=/^((https?|ftp|smtp):\/\/)?(www.)?[a-z0-9]+(\.[a-z]{2,}){1,3}(#?\/?[a-zA-Z0-9#]+)*\/?(\?[a-zA-Z0-9-_]+=[a-zA-Z0-9-%]+&?)?$/;
a.map(x=>console.log(x+" => "+re.test(x)));

edited Mar 6, 2017 at 7:51

answered Mar 6, 2017 at 6:59

Sagar V

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16 Comments

Sagar V Over a year ago

added support for sample.com#

Talk is Cheap Show me Code Over a year ago

this does not support. www.google.co.in

Malinda Over a year ago

Hi, To support URLs like https://code.tutsplus.com/tutorials/8-regular-expressions-you-should-know--net-6149 , i think you should change (#?\/?[a-zA-Z0-9#]+) to (#?\/?[a-zA-Z0-9-_#]+)

smartmouse Over a year ago

This does not support URL like "web-site.com" or "web-site.com"

Kishore Barik Over a year ago

Doesn't support http://blog.example.com

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Mustofa Rizwan · Accepted Answer · 2022-03-01 09:12:28Z

15

You can try this:

^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?\/?$

Updated Demo

const regex = /^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?\/?$/gm;
const str = `http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com
www.sample.com
mofiz.com
kolim.com
www.murikhao.www.sample.com
http://murihao.www.sample.com
http://www.sample.com/xyz?abc=dkd&p=q&c=2
www.sample.gov.bd
www.sample.com.en
www.sample.vu
www.sample.u/


`;
let m;

while ((m = regex.exec(str)) !== null) {

    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    console.log("matched :"+m[0]);
}

edited Mar 1, 2022 at 9:12

answered Mar 6, 2017 at 7:02

Mustofa Rizwan

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9 Comments

Dheeraj Agrawal Over a year ago

this doesn't support subdomain (I should have added that to my list) also it should support other top level domains .tv, .in, .co.in all this are valid

Mustofa Rizwan Over a year ago

yeah you should have :) the base of my answer was to have sample.com, help me define the base, to have answer of your liking

Dheeraj Agrawal Over a year ago

yeah so it could be anything, it could contain any top level domain, any domain name (not only sample), protocol, query strings & hash

Mustofa Rizwan Over a year ago

:D :D I thought you were only talking about sample.com in the first place , plz take a look now :P

Mustofa Rizwan Over a year ago

@DheerajAgrawal does this solve your problem now ?

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