traverse bash array including empty elements

Question

array=('' '' 2 4); for f in ${array[@]}; do echo a; done
a
a

I expected four "a" rows here as there are 4 elements of array

$ echo ${#array[@]}

"${array[@]}". many many duplicate questions will be found. — rici
– rici, Commented Mar 6, 2017 at 15:13
Also, please follow this advice from the tag info before asking questions with bash: "For shell scripts with errors, please check them in shellcheck.net before posting here." — rici
– rici, Commented Mar 6, 2017 at 15:34
Thank you rici, shellcheck gave right answer. I didnt notice that advice — xoid
– xoid, Commented Mar 7, 2017 at 7:00

gmu · Accepted Answer · 2017-03-06 15:16:14Z

1

You must quote the variable for correct using:

array=('' '' 2 4); for f in "${array[@]}"; do echo a; done

and btw. search for simular answers :)

answered Mar 6, 2017 at 15:16

gmu

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1 Comment

Thank you. Was unable to find. Honestly.