PHP scope issue in anonymous function

Question

so I have these functions

function a(){
    int c = 1;
    b(function(){echo $c;});
}

function b($code){
    $code();
}

but somehow $c becomes undefined in the anonymous function I know it's bacause that the anonymous function is it's own scope, but is there someway to make this work?

Is this PHP? Because you've tagged it as PHP, but your code isn't — Mark Baker
– Mark Baker, Commented Mar 7, 2017 at 8:21

sensorario · Accepted Answer · 2017-03-07 08:21:29Z

1

Yes: you can use "use" statement.

function a()
{
    $c = 1;
    b(function() use ($c) {
        echo $c;
    });
}

function b($code){
    $code();
}

answered Mar 7, 2017 at 8:21

sensorario

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Comments

Đào Minh Hạt · Accepted Answer · 2017-03-07 08:22:19Z

0

http://php.net/manual/en/language.variables.scope.php

When you put $c inside a function it's considered to be a local scope variable.

answered Mar 7, 2017 at 8:22

Đào Minh Hạt

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