How to wait callback inside recursive function

Question

I have a recursive function:

let main = () => {
  ftp(_defaultPath, _start, (file, doc, name) => {
    parser(file, doc, name)
  })
}

The parser function:

module.exports = async function (file, doc, name) {
    await funcOne(file, doc)
    await funcTwo(file, doc, name)
    await funcThree(file, doc, name)
}

The callback its called inside the recursive function multiple times:

async function myFuntion(path, name, callback) {
   ...
   callback(file, doc, files[p][1])
   ...
}

The problem is I want to wait when i do callback like:

async function myFuntion(path, name, callback) {
   ...
   await callback(file, doc, files[p][1])
   ... next lines need to wait to finish callback
}

I trying to find how to do that.

It's possible to do that? thanks

rsp · Accepted Answer · 2017-03-07 17:26:26Z

1

It's possible to do that?

Yeah, it's possible to use await but for this to work:

await callback(file, doc, files[p][1])

your callback() needs to return a promise. From your code it's not clear that it does.

answered Mar 7, 2017 at 17:26

rsp

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1 Comment

user2634870 Over a year ago

Thanks! Just i found the solution :D

user2634870 · Accepted Answer · 2017-03-07 17:53:17Z

1

I have done on this way:

I edit my main function with async inside ftp function:

let main = () => {
  ftp(_defaultPath, _start, async (file, doc, name) => {
    await parser(file, doc, name)
  })
}

I added the promise to parser function like that:

module.exports = function (file, doc, name) {
    return new Promise( async (resolve, reject) => {
        try {
            await funcOne(file, doc)
            await funcTwo(file, doc, name)
            await funcThree(file, doc, name)
        } catch(e) {
            return reject(e)
        }
        return resolve()
    }
}

Inside the recursive function I do the await.

await callback(file, doc, files[p][1])

Now waits as expected.

Thanks!

answered Mar 7, 2017 at 17:53

user2634870

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