Image Upload Using PHP Mysql

Question

This code does not print the temporary name of the uploaded image as well does not upload any picture in my Photo folder. but print image name. it work others computer correctly . where is the problem? please help me. i am using php Version 5.6.20

<!DOCTYPE html>
<html>
<head>
  <title>Image Upload</title>
</head>

<body>
<?php 

if ($_SERVER["REQUEST_METHOD"] == "POST") 
{

  $destination = "Photo/".$_FILES['image']['name'];
   $filename    = $_FILES['image']['tmp_name'];   
  echo $destination; 
  echo "<br/>";
  echo $filename;   
  echo "<br/>";

  if (file_exists($destination))

 echo "Sorry, file already exists.";

 else
    move_uploaded_file($filename, $destination);
  $name=$_FILES['image']['name'];
  $tmp_name=$_FILES['image']['tmp_name'];

  echo $tmp_name;
}


?>

<form method="POST" enctype="multipart/form-data">

<table>

<tr>
   <td>Choose Image</td>
   <td><input type="file" name="image"/> </td>
</tr> 

<tr>
   <td>Description:</td>
   <td><textarea name="Description" rows="4" cols="40"/></textarea></td>
</tr>

<tr> 
   <td></td>

    <td> <input type="submit" name="submit_image" value="Submit"></td>
</tr> 
</table>
</form>

</body>
</html>

Dipali Sakle Systematix · Accepted Answer · 2017-03-08 05:50:30Z

2

<!DOCTYPE html>
<html>
<head>
  <title>Image Upload</title>
</head>

<body>
<?php 

if(isset($_POST['submit_image'])) 
{

  $destination = "Photo/".$_FILES['image']['name'];
   $filename    = $_FILES['image']['tmp_name'];   
  echo $destination; 
  echo "<br/>";
  echo $filename;   
  echo "<br/>";

  if (file_exists($destination))

 echo "Sorry, file already exists.";

 else
    move_uploaded_file($filename, $destination);
  $name=$_FILES['image']['name'];
  $tmp_name=$_FILES['image']['tmp_name'];

  echo $tmp_name;
}


?>

<form method="POST" enctype="multipart/form-data">

<table>

<tr>
   <td>Choose Image</td>
   <td><input type="file" name="image"/> </td>
</tr> 

<tr>
   <td>Description:</td>
   <td><textarea name="Description" rows="4" cols="40"/></textarea></td>
</tr>

<tr> 
   <td></td>

    <td> <input type="submit" name="submit_image" value="Submit"></td>
</tr> 
</table>
</form>

</body>
</html>

I tried this code it is working for me. please give read write permission of your photo folder I think it will work for you.

edited Mar 8, 2017 at 5:50

answered Mar 8, 2017 at 5:32

Dipali Sakle Systematix

8856 silver badges19 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Dipali Sakle Systematix Over a year ago

what is the problem occur

Ramzan Over a year ago

in my code i print uploaded image name and temporary name of that image and upload that image in a folder name 'Photo'. but problem is it print only name of this image but not print temp_name and not upload any image in my photo folder

Dipali Sakle Systematix Over a year ago

please give 777 permission on your photo folder

Ramzan Over a year ago

sorry, its not working. i told it work other computer but not work in my computer i don't know what is the problem. thank you for your answer and comment

Prithabai R · Accepted Answer · 2017-03-08 05:55:00Z

1

your code is working fine , check with 'Photo/' folder permission and tmp folder path too. ex : D:\xampp\tmp\phpDCD9.tmp.

answered Mar 8, 2017 at 5:55

Prithabai R

582 bronze badges

2 Comments

Prithabai R Over a year ago

try to put error_reporting(0); inside the script and check , what type of the error is getting

Ramzan Over a year ago

after print error_reporting(0) it showing output 22527. i don't understant this

Kathirmalan · Accepted Answer · 2017-03-08 05:55:59Z

1

Your code is perfectly working on my machine. I think you might want to check the directory name Photo to which the uploaded files are been stored. check your destination folder name inn your coding and defined folder name where your project is present are same. Kindly post your error or warning message so that it is easy to help.

answered Mar 8, 2017 at 5:55

Kathirmalan

661 silver badge8 bronze badges

1 Comment

Ramzan Over a year ago

i think everything is ok. i told that it work other computer but not working my computer. shit

Nishit Manjarawala · Accepted Answer · 2017-03-08 05:24:59Z

0

i think this part write properly like this it will solve

if (file_exists($destination)){
 echo "Sorry, file already exists.";
 }else{
    move_uploaded_file($filename, $destination);
  $name=$_FILES['image']['name'];
  $tmp_name=$_FILES['image']['tmp_name'];
  echo $tmp_name;
}

answered Mar 8, 2017 at 5:24

Nishit Manjarawala

4614 silver badges20 bronze badges

4 Comments

Ramzan Over a year ago

done but not working, i don't know why its not printing temp_name in my computer. but it works other computer

Nishit Manjarawala Over a year ago

not working it dosent mean you give wrong review to my question like that nobody will answer

Ramzan Over a year ago

dear i am not give that wrong review. you are trying to solve my problem why i give your comment wrong review?

Nishit Manjarawala Over a year ago

some one give negative rank to my comment

Collectives™ on Stack Overflow

Image Upload Using PHP Mysql

4 Answers 4

4 Comments

2 Comments

1 Comment

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

4 Comments

2 Comments

1 Comment

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related