Python: Combine AND and NOT operators? [duplicate]

Question

if (cond1 and cond2) or (not cond1 and not cond2):

Is there a simpler way to write this in Python?

You want the inverse of xor, (so xand?), which is bool(cond1) == bool(cond2). See the duplicate (with != inverted to ==). You can drop the bool() calls if both cond1 and cond2 are themselves boolean results. — Martijn Pieters
– Martijn Pieters, Commented Mar 9, 2017 at 3:58
@MartijnPieters: OK. The logic is correct; the question still asks about equality of both variables (both true or both false). Fill in the correct syntax for the language, whether that's =, ==, equals, or something else. :-) — Ken White
– Ken White, Commented Mar 9, 2017 at 4:00
@SamuelLiew: yes, which is nothing more than the inversion of XOR. So bool(a) != bool(b) (XOR) becomes bool(a) == bool(b). I do cover that in my comment. — Martijn Pieters
– Martijn Pieters, Commented Mar 9, 2017 at 4:09

Paul Panzer · Accepted Answer · 2017-12-12 07:52:45Z

3

If cond1 and cond2 are booleans, there certainly is:

cond1 == cond2

answered Mar 9, 2017 at 3:54

Paul Panzer

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1 Comment

Completely forgot about that. Thanks!