How to post two variables with jQuery AJAX

Question

How to post two variables with jQuery AJAX? One variable work fine but two variables not working

function get() {
    $('#age').hide();
    $.post('jrecomment2.php',{ userID: form.userID.value },{ id_number: form.id_number.value }

    function(output){

        $('#age').html(output).slideDown(2000);


        });

}

and the form:

<form name="form" dir="rtl">
    <input type="text" name="userID">
    <input type="text" name="id_number">
    <input type="button" value="submit" style=" width: 120;" onClick="get();"> 

</form>

Grim... · Accepted Answer · 2017-03-09 13:12:24Z

2

You need to use { userID: form.userID.value, id_number: form.id_number.value }.

answered Mar 9, 2017 at 13:12

Grim...

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1 Comment

Moustafa Elbeda Over a year ago

Thank you very much

Nitesh Gupta · Accepted Answer · 2017-03-09 13:19:22Z

0

$.post('jrecomment2.php',{ userID: form.userID.value, id_number: form.id_number.value }, function(output){ });

answered Mar 9, 2017 at 13:19

Nitesh Gupta

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Comments

Shafiqul Islam · Accepted Answer · 2017-03-09 13:30:32Z

0

you can use this code

 $.ajax({
            type: "POST",
            url: 'jrecomment2.php',
            data: 'userID=' + form.userID.value+'&id_number='+form.id_number.value,
            dataType: 'text',
            async: false,
            cache: false,
            success: function (output) {

            $('#age').html(output).slideDown(2000);
            }
        });

and post method

$.post('jrecomment2.php',{ userID: form.userID.value, id_number:     form.id_number.value }, function(output)
 { 
   $('#age').html(output).slideDown(2000);
 }
);

answered Mar 9, 2017 at 13:30

Shafiqul Islam

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