How to pass file.py using http.server in command line as parameter?

Question

Consider a simple server.py

from http.server import CGIHTTPRequestHandler, HTTPServer
PORT = 5005
handler = CGIHTTPRequestHandler
handler.cgi_directories = ['/']  # this is the current directory
server = HTTPServer(('localhost', PORT), handler)
print ('Server is ready at', PORT, 'PORT')
server.serve_forever()

If I call this file using python.exe -u server.py in command line I'll be able to serve a python script in '/' main directory.

I could use also python -m http.server --bind localhost --cgi 5005 directly.

In both cases I need to open in the browser a specific python file, lets say: http://localhost:5005/myfunction.py

Is there an alternative to include the file.py using http.server directly in command line?

For example, something equivalent to micro -p 5005 file.js according to micro npm module?

Algo for doing it ,,, let x = base url of the server and y = x+pythonfile .. just remove the x part from y you get the file nam e.. — Ankur Jyoti Phukan
– Ankur Jyoti Phukan, Commented Mar 11, 2017 at 20:22
do you mean redirect just localhost:5005/ (the root directory) to a file? I am unfarmiliar with what micro is so I have no idea what you are actually asking for... — Tadhg McDonald-Jensen
– Tadhg McDonald-Jensen, Commented Mar 11, 2017 at 20:32
@TadhgMcDonald-Jensen Yes. redirect localhost:5005/ to a specific file using command line. — estebanpdl
– estebanpdl, Commented Mar 11, 2017 at 20:33
hmm, I will dig up relevent source code, I do know if there is an index.html it will automatically redirect to that. — Tadhg McDonald-Jensen
– Tadhg McDonald-Jensen, Commented Mar 11, 2017 at 20:34

Tadhg McDonald-Jensen · Accepted Answer · 2017-03-27 15:05:00Z

1

it seems redirecting to anything other then index.html or index.htm (or a list of files) is not supported by the base code:

    #if <path is a directory>:

        for index in "index.html", "index.htm":
            index = os.path.join(path, index)
            if os.path.exists(index):
                path = index
                break
        else:
            return self.list_directory(path)

one solution would be to simply modify the original source so the tuple ("index.html", "index.htm") points to something that can more easily be altered at runtime. Alternatively you can define your own wrapper that makes the check yourself, basically just copy the whole def send_head function and override that loop to just assign path to the file you want to redirect to.

Wish I had a solution that doesn't involve rewriting the source code but I can't think of another (sane) solution.

edited Mar 27, 2017 at 15:05

answered Mar 11, 2017 at 20:44

Tadhg McDonald-Jensen

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1 Comment

estebanpdl Over a year ago

I think is a great solution. I'll check this alternative. Thanks for your help.

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