I cannot call jqgrid using the . operator as given in the examples:
jQuery("#grid_id").editGridRow( "new", options );
I get the following error:
jQuery("#grid_id").editGridRow is not a function
Instead I always have to make a call in the following way:
jQuery("#grid_id").jqGrid("editGridRow", "new", options );
I don't have any problems with the latter approach - I am curious why the former does not work for me, when most examples and tutorials using the former approach
Thanks
Probably you used the following code
jQuery.jgrid.no_legacy_api = true;
somewhere in you program either directly or indirectly (see documentation). The code prohibit the usage of "old style" API.
By the way if you prefer the usage of the "old style" API because of IntelliSense support in the Visual Studio you can use the "new style" API in a little other form:
jQuery("#grid_id").jqGrid.editGridRow ("new", options);
instead of
jQuery("#grid_id").jqGrid ("editGridRow", "new", options);
In the case there are no conflicts with another jQuery Plug-Ins which described Nick Craver, but the IntelliSense will continue work:
and
This is just the way the plugin designers chose to do it. The alternative is to have all of their methods on $.fn (present on the prototype, so on every jQuery object), which has a few issues:
The list of methods jqGrid has isn't short, so this is a way for them to keep it under control and compartmentalized. Also, this isn't unique to jqGrid...for example the jQuery UI theming it accepts, all of the widgets in that library follow the same convention.
