Using default values in Python mixed with input parameters

Question

I have function that looks like this:

def CreateURL(port=8082,ip_addr ='localhost',request='sth'):
    return str("http://" + ip_addr+":"+str(port) + '/' + request)

Now I want to use the default parameter for port and request but not for ip_addr. How do I have to write the function in this case?

CreateURL('192.168.2.1')

Does not work since itwill override the port and not the ip_addr

timgeb · Accepted Answer · 2017-03-14 12:55:44Z

6

Pass the parameter explicitly.

>>> def foo(a=1, b=2, c=3):
...     print(a, b, c)
... 
>>> foo(c=4)
(1, 2, 4)

answered Mar 14, 2017 at 12:55

timgeb

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Comments

Ari Cooper-Davis · Accepted Answer · 2017-03-14 12:56:08Z

3

url = CreateURL(ip_addr='192.168.2.1')

answered Mar 14, 2017 at 12:56

Ari Cooper-Davis

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doctorlove · Accepted Answer · 2017-03-14 12:56:45Z

2

Simply state the name of the parameter you wish to specify like this:

>>> CreateURL(ip_addr = '192.168.2.1')
'http://192.168.2.1:8082/sth'

answered Mar 14, 2017 at 12:56

doctorlove

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Harsha Biyani · Accepted Answer · 2017-03-14 13:02:50Z

1

You can simply pass parameter explicitly

>>> CreateURL(ip_addr = "192.168.2.1")
'http://192.168.2.1:8082/sth'

answered Mar 14, 2017 at 13:02

Harsha Biyani

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