Iterating over a list of lambda functions in python, given the same parameter

Question

I want to make a lambda function of x such that takes the maximum between the results of all lambda functions in a list for that given x.

Any ideas on how to make this functional for any size of list?

a = lambda(x): someprocess0(x)
b = lambda(x): someprocess1(x)
c = lambda(x): someprocess2(x)

funcList = [a, b, c]

function = lambda(x): max(funcList[0](x), funcList[1](x), funcList[2](x))

Martijn Pieters · Accepted Answer · 2017-03-15 05:34:47Z

3

You can use a generator expression to apply x to each function:

function = lambda x: max(f(x) for f in funcList)

This avoids keeping all function results in memory in a list, when you only need to track the highest value found so far.

You might be interested in the Python Functional Programming HOWTO included in the Python documentation, which teaches about generator expressions and other functional techniques.

answered Mar 15, 2017 at 5:34

Martijn Pieters

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Comments

Dani Medina · Accepted Answer · 2017-03-15 05:30:11Z

0

Using the following function:

def computeResults(functions, value):
    res = []
    for f in functions:
        res.append(f(value))
    return res

function = lambda x: max(computeResults(funcList, x))

answered Mar 15, 2017 at 5:30

Dani Medina

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