getting 404 not found when submitting form using ajax in laravel

Question

I am new with laravel, I am having an issue when posting my data to controller in laravel while using ajax. My view contains a select box which is populated from database when a user select a value from select box i am trying to call ajax which will return details of salary of the user.The issue is it gives me 404 not found error.

The Code for the controller file is shown below.

    this function is defined inside a controller

    public function getPostSalary()
        {
            echo "ajax called";
            return 'true';
        }

The Routes file is

Route::post('company/salary-user', 'CompanyController@getPostSalary');

this is my ajax code from where the controller is being calleD

<script>
    $(document).ready(function() {
        $('#employee').change(function () {
            var values = $('#employee').val();
            if (values == '') {
                $.pnotify({
                    title: 'Message',
                    text: 'Please Select a User.',
                    type: 'error',
                    delay: 3000
                });
                return false;
            }
            var csrf = $('#csrf').val();
            $.ajax({
                url: '{!! URL::to("company/salary-user")!!}',
                type: "POST",
                data: { user_id: values, _token: csrf },
                cache: false,
                beforeSend: function () {

                },
                success: function (data) {
                    console.log(data);
                    $('#loader').hide();
                }
            });
        }); 
    });
</script>

Can someone help me to figure out what is the issue and what should be done to call my function.

and in your network tracking, whats is the url you are pointed to when event employee change happens ? — hassan
– hassan, Commented Mar 20, 2017 at 12:12

Niklesh Raut · Accepted Answer · 2017-03-20 12:27:17Z

2

Single quotes is for string so your url is not generating as you expecting. Use like this

  url : "{!! URL::to('company/salary-user')!!}",

answered Mar 20, 2017 at 12:27

Niklesh Raut

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Comments

hassan · Accepted Answer · 2017-03-20 12:48:14Z

0

You can use direct url like

 $.ajax({
            url:'company/salary-user',
            type: "POST",
            data: { user_id: values, _token: csrf },
            cache: false,
            beforeSend: function () {

            },
            success: function (data) {
                console.log(data);
                $('#loader').hide();
            }
        });

edited Mar 20, 2017 at 12:48

hassan

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answered Mar 20, 2017 at 12:43

Mukesh Sharma

16

Comments

hassan · Accepted Answer · 2017-03-20 12:54:45Z

0

replace this line:

{!! URL::to("company/salary-user")!!}

by :

{{ url('/company/salary-user') }}

or

{{ route('/company/salary-user') }}

edited Mar 20, 2017 at 12:54

answered Mar 20, 2017 at 12:08

hassan

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13 Comments

Ashutosh Parashar Over a year ago

it is giving me the same issue with that

hassan Over a year ago

LOL ,omg i was so dump, use either {{ url('/company/salary-user') }} or {{ route('/company/salary-user') }}

Ashutosh Parashar Over a year ago

the issue is at it place

hassan Over a year ago

what's the actual url now you are pointed to ? and don't forget to clear your browser cache

hassan Over a year ago

and when using url('/company/salary-user') ?

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