Delayed text in python

Question

Similar to my last question: Delayed text (Need it more efficiently delayed) C++. I need to make more efficiently delayed text in python. I tried to alter the other function to make it work but I couldn't get it to work.

Sounds simple. Loop over every character in the text. In the loop body use print and sleep. Where's your problem? — Matthias
– Matthias, Commented Mar 21, 2017 at 21:25
I don't know how to do that, could you send a code example. I just started python yesterday. — ActiveGaming
– ActiveGaming, Commented Mar 21, 2017 at 21:30

andria_girl · Accepted Answer · 2017-03-21 22:41:39Z

1

def delay_print(text, delay):
    for i in text:
        time.sleep(delay)
        print(i, end='')
        sys.stdout.flush()
    print()

This is just loops through the given text and uses end='' to not print a new line until the loop finishes

edited Mar 21, 2017 at 22:41

answered Mar 21, 2017 at 21:30

andria_girl

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7 Comments

Matthias Over a year ago

Why the name sPrint for the function? Why not stick to the Style Guide for Python Code and call the function delayed_print or something like that?

andria_girl Over a year ago

I actually didn't know there was a naming convention, I usually just name things like that. Thanks for showing me that though

ActiveGaming Over a year ago

how do I call the function, I figured out with the other one it is poketext("Text Here") but I can't seem to figure it out with this one

andria_girl Over a year ago

Seriously?? You call it with your string and your delay, delay_print("here is a string but you can use a variable too", 0.05)

andria_girl Over a year ago

0.05 is the time in seconds between each character print

|

Keith k · Accepted Answer · 2017-03-21 21:29:41Z

0

import time

msg = "helloworld"
for char in msg:
    print char
    time.sleep(1) #seconds

Did you try something like this?

answered Mar 21, 2017 at 21:29

Keith k

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