Java - String conversion

Split the strings based on ,, sort the resulting arrays, then use Assert.assertArrayEquals to compare the arrays

You can split them and sort the array and then check whether they're equal or not.

String actual = "10684 ANNA MARIE DR, GLEN ALLEN, VA, APT 111, 23060";
String expected = "10684 ANNA MARIE DR, APT 111, GLEN ALLEN, VA 23060";

String arr1[] = actual.split(", ");
String arr2[] = expected.split(", ");

Arrays.sort(arr1);
Arrays.sort(arr2);

Assert.assertArrayEquals( arr1, arr2 );

You can always do it in that a little stupid way:

String actual = "10684 ANNA MARIE DR, GLEN ALLEN, VA, APT 111, 23060";
String[] arr = actual.split(", ");
String result = arr[0] + ", " + arr[3] + ", " + arr[1] + ", " + arr[2] + " " + arr[4];

You should replace that String with Address class and then easily compare addresses. In Effective Java book you can find chapter where they say that String is not good to use to replace some other structure(and obviously you have address structure here).

Unlike others suggested, that is splitting by ,, arrays aren't going to be equal.

VA and 23060 will result in two different elements, while in the expected String they are a single element.

A clarification from OP is needed.

String actualArray[] = actual.split(",");
int i = 0;

String finalStr = actualArray[i] +","+actualArray[i+3]+","+actualArray[i+1]+","+actualArray[i+2]+actualArray[i+4];
System.out.println(finalStr);