php: Create an array with ascending date objects

Question

I would like to create an array which consists of ascending date objects. I tried the following code:

$dat=date_create_from_format("Y-m-d H:i:s", "2014-11-01 00:00:00");
for ($i=0; $i<=2; $i++) {
    $ar[$i]=$dat;
    $dat->modify('+1 day');
}
print_r($ar);

The result is three times the same date:

Array
(
    [0] => DateTime Object
        (
            [date] => 2014-11-04 00:00:00.000000
            [timezone_type] => 3
            [timezone] => Europe/Berlin
        )

    [1] => DateTime Object
        (
            [date] => 2014-11-04 00:00:00.000000
            [timezone_type] => 3
            [timezone] => Europe/Berlin
        )

    [2] => DateTime Object
        (
            [date] => 2014-11-04 00:00:00.000000
            [timezone_type] => 3
            [timezone] => Europe/Berlin
        )

)

But what I would like to get is:

   Array
    (
        [0] => DateTime Object
            (
                [date] => 2014-11-01 00:00:00.000000
                [timezone_type] => 3
                [timezone] => Europe/Berlin
            )

        [1] => DateTime Object
            (
                [date] => 2014-11-02 00:00:00.000000
                [timezone_type] => 3
                [timezone] => Europe/Berlin
            )

        [2] => DateTime Object
            (
                [date] => 2014-11-03 00:00:00.000000
                [timezone_type] => 3
                [timezone] => Europe/Berlin
            )

    )

Someone has an idea? Probably a newbie-thing ;-)

u_mulder · Accepted Answer · 2017-03-22 14:54:16Z

1

As $dat is an obejct, all items in $ar store references to this object. So, when this object changes ($dat->modify()), all references immediately see this changes. To create different object, you can clone source object:

$dat = date_create_from_format("Y-m-d H:i:s", "2014-11-01 00:00:00");
for ($i = 0; $i <= 2; $i++) {
    $ar[$i] = clone $dat;
    $dat->modify('+1 day');
}
print_r($ar);

Here clone operator takes you current $dat object and makes a copy of it. So when you change $dat again, copy doesn't know about it.

answered Mar 22, 2017 at 14:54

u_mulder

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