Lua String replace

Question

How would i do this?

I got this:

name = "^aH^ai"
string.gsub(name, "^a", "")

which should return "Hi", but it grabs the caret character as a pattern character

What would be a work around for this? (must be done in gsub)

Because ^ is a special character, you need use % to escape it in Lua. — Huang F. Lei
– Huang F. Lei, Commented Nov 30, 2010 at 2:03

Dave Jarvis · Accepted Answer · 2014-02-25 07:40:40Z

113

Try:

name = "^aH^ai"
name = name:gsub("%^a", "")

See also: http://lua-users.org/wiki/StringLibraryTutorial

edited Feb 25, 2014 at 7:40

Dave Jarvis

31.3k43 gold badges186 silver badges326 bronze badges

answered Nov 28, 2010 at 16:33

Kknd

3,2671 gold badge28 silver badges30 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Anderson Green Over a year ago

The tutorial uses a slightly different syntax. Why is gsub written with a : instead of a . in this answer?

0xC0000022L Over a year ago

@AndersonGreen: it can be called as a library function of the string library or as a method on a string object. The : is syntax sugar in Lua which effectively implies the object on which the method is called being passed as first parameter.

Diceyus Over a year ago

What if we want to replace special characters with special character? like email = email:gsub("%+", "%2b"). Effectively we want to to URL Encode the + to %2b

Collectives™ on Stack Overflow

Lua String replace

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related