array_filter not working for multi dimensional array

Question

Here is the non-functional code. It does not return anything. Not quite sure what is wrong with the syntax I am using.

 function findNeedle($array, $needle) {
        return array_values(array_filter($array, function($arrayValue) use($needle) { return $arrayValue['lp_url'] == $needle; } ));
 }
 $myarray =
         0 =>
         array (
           'lp_url' => 'http://example.com/nx/?utm_source=aa&utm_medium=referral',
           'lp_term_id' => 1435949468,
           'aff_term_id' => 1445295565,
           'offer_term_id' => 1445295996,
             ),
         1 =>
         array (
            'lp_url' => 'http://example.org/nx/?utm_source=aa&utm_medium=referral',
            'lp_term_id' => 1435949468,
            'aff_term_id' => 1445295559,
            'offer_term_id' => 1445295989,
            ),
         );

$needle = 'http://example.com/nx/?utm_source=aa&utm_medium=referral';
if (is_array($myarray)) {
foreach ($myarray as $value) {
    if (is_array($value))
    {
        $x = findNeedle($value, $needle);
    }
}

Maybe describe what you want. Since the code is non-functional it doesn't tell us much. — AbraCadaver
– AbraCadaver, Commented Mar 23, 2017 at 18:48
If the code returns true if the match is found and a false if match is not found (in lp_domain key), it would work for me. — hvs
– hvs, Commented Mar 23, 2017 at 19:24
in_array($needle, array_column($myarray, 'lp_url')); returns true or false if matched or not. — AbraCadaver
– AbraCadaver, Commented Mar 23, 2017 at 19:29
Thanks. That works. Also this works: if(array_search($needle, array_column($myarray, 'lp_url')) !== False) { echo "FOUND"; } else { echo "Not Found"; } — hvs
– hvs, Commented Mar 23, 2017 at 19:43
Yes, that's a good one, but array_search returns a key so you have to compare with false as you have done. in_array returns true or false. — AbraCadaver
– AbraCadaver, Commented Mar 23, 2017 at 19:55

AbraCadaver · Accepted Answer · 2017-03-23 19:54:08Z

1

Extract an array of the data for the lp_url column and check for $needle:

if(in_array($needle, array_column($myarray, 'lp_url'))) {
    echo "Found";
} else {
    echo "Not found";
}

answered Mar 23, 2017 at 19:54

AbraCadaver

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