Variable assignment in function doesn't return it after the function is called

Question

I have a function get_arcs():

for i in rng:
    if not lines[i].startswith('[') and 'echo $ORACLE_SID' in lines[i].strip():
            sid = lines[i + 2]
            yield sid
    if lines[i].strip().find('SELECT') == 0:
        res = lines[i:]
        for i in res:
            print >> f, i.strip()
            yield i.strip()

which supposed to:

assign a certain value to variable sid
write different content to f-file
have the generator of i.strip() as the output which will be passed the to another function and the sum of certain objects will be calculated

The problem is when the get_arcs() is called:

for line in get_arcs():
    if len(line.split()) == 13:
        lst.append(int(line.split()[-5]))
print sum(lst), 'Bytes'

It does return the sum(lst) as expected, but how can I retrieve my sid value, as I cannot call it anywhere outside of the function.

Nathan · Accepted Answer · 2017-03-24 08:38:29Z

1

So, you need this function to return both i.strip() and sid? I always find it a code smell when you try to return two values from a single function. But if it really is necessary in this case, I would return a tuple.

yield i.strip(), sid

Later:

for (line, sid) in get_arcs():
    # both line and sid are defined here

answered Mar 24, 2017 at 8:38

Nathan

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2 Comments

feedthemachine Over a year ago

Yes, this worked just fine. Thanks a lot! P.S. yes I do need 1 func to return two values, since there is a paramiko ssh connection gets established as well.

Nathan Over a year ago

Of course, there's an exception to every rule. It's just always worth double checking in these cases. ;)

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