I have the followings string from the DB "[["22-1-2017;10:00-19:00"],["22-1-2017;10:00-19:00"]]"
Is there an easy way to transform the string into an arrayList?
Thanks in advance
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That depends on what your definition of the word "easy" is. If you have nested structure as you showed us, in general you'd want to use some sort of parser to read it in.Tim Biegeleisen– Tim Biegeleisen2017-03-24 09:56:34 +00:00Commented Mar 24, 2017 at 9:56
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An ArrayList of what? Strings?user6073886– user60738862017-03-24 09:56:39 +00:00Commented Mar 24, 2017 at 9:56
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@OH GOD SPIDERS yes of strings like [["22-1-2017;10:00-19:00"],["22-1-2017;10:00-19:00"]]jValls– jValls2017-03-24 10:01:06 +00:00Commented Mar 24, 2017 at 10:01
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1you could use a json parser...User9123– User91232017-03-24 10:03:47 +00:00Commented Mar 24, 2017 at 10:03
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2@jValls your example "of strings like [["22-1-2017;10:00-19:00"],["22-1-2017;10:00-19:00"]]" shows List of Lists of String, not List of String. Please clarify it.Pshemo– Pshemo2017-03-24 10:14:15 +00:00Commented Mar 24, 2017 at 10:14
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3 Answers
How about using JSON parser like gson?
String jsonArray = "[[\"22-1-2017;10:00-19:00\"],[\"22-1-2017;10:00-19:00\"]]";
Type listType = new TypeToken<List<List<String>>>(){}.getType();
List<List<String>> list = new Gson().fromJson(jsonArray, listType);
System.out.println(list);
Output: [[22-1-2017;10:00-19:00], [22-1-2017;10:00-19:00]]
1 Comment
jValls
works perfect! Just what I need it simple and effective. I also imported the followings packages for Type and TypeToken: import com.google.gson.reflect.TypeToken; import java.lang.reflect.Type;
Try this,
String a = "[[\"22-1-2017;10:00-19:00\"],[\"22-1-2017;10:00-19:00\"]]";
String[] b = a.replace("[", "").replace("]", "").replace("\"", "").split(",");
List<String> c = Arrays.asList(b);
Output = [22-1-2017;10:00-19:00, 22-1-2017;10:00-19:00]
2 Comments
User9123
assuming that the dates does not contains
[, ] nor ", it works only if the result must be a flatten List<String>, not a List<List<String>>
kenn3th
String.replace() will return the original value if occurrence not found. Is there any reason to flatten the result to List<List<String>> if it could be flatten to List<String>?
I got one solution for your problem, if you want the date in an String Array:
String s = "[[\"22-1-2017;10:00-19:00\"],[\"22-1-2017;10:00-19:00\"]]";
// first remove outter brackets
s = s.substring(1, s.length());
s = s.substring(0, s.length()-1);
// Create a Pattern for getting everything within brackets
Pattern r = Pattern.compile("\\[(.*?)\\]");
// Now create matcher object.
Matcher m = r.matcher(s);
List<String> l = new ArrayList<>();
while (m.find()) {
l.add(m.group(1));
}
System.out.println(l);
If you want it without the quotations use
Pattern r = Pattern.compile("\\[\"(.*?)\"\\]");
Hope this helps
Edit: If you use the
Pattern r = Pattern.compile("\\[\"(.*?)\"\\]");
you do not need to remove the outer brackets at all, as it already looks for content within:
- opening square brackets with double quotations
- double quotations with closing square brackets
