I created a simple 3D array in Python I need to print it in rows.
apple=[[["SNo."],["Computers"],["Mobile"]],
[["1"],["iMac"],["iPhone"]],
[["2"],["Macbook"],["iPod"]]]
I want it to be printed like below:
SNo. Computers Mobile
1 iMac iPhone
2 Macbook iPod
You can do that with:
for l in apple:
print(*[e[0] for e in l])
But frankly, since the final elements are all one-element list, I think you should change the code that creates it to have a 2D array to start with. Everything will be easier that way.
That data looks 2D to me. If you really want to print a 3D array, then you can avoid writing any loops yourself and use numpy:
import numpy as np
apple_np = np.array(apple)
print apple_np
Your data, however isn't 3D, so it won't print out as you envisage. What you need is a 2D array:
apple=[["SNo.", "Computers", "Mobile"],
["1", "iMac", "iPhone"],
["2", "Macbook", "iPod"]]
apple_np = np.array(apple)
print apple_np
If you're using python 2.7, you can use the following to print out the table in a nice format:
width = max([len(el) for row in apple for el in row]) + 1
for row in apple:
for el in row:
print ("{:"+str(width)+"s}").format(el),
print ""
it should works:
for i in apple:
for j in i:
helper.append(j)
counter = 0
assistant = []
for x in helper:
counter += 1
assistant.append(x[0])
if counter == 3:
print(" ".join(assistant))
counter = 0
assistant = []
