Array using double

Question

This is the code that I made.... for the array code

public class main
{
  public static int arraySum(int[] arr)
  {
    int result = 0;
    for (int i = 0; i < arr.length; i++)
    {
      result += arr[i];
    }
    return result;
  }
  public static int arraySumBetter(int [] a)
  {
    int result = 0;
    for (int value : a)
    {
      result += value;
    }
    return result;
  }

  public static void main(String [] args)
  {
    double[] a ={0,2,3,1,0.56};
    System.out.format("%.1f", (double) arraySumBetter(a));
  }
}

when I run it it prints an error out:

typed.java:25: error: incompatible types: double[] cannot be converted to int[] System.out.format("%.1f", (double) arraySumBetter(a));

Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output1 error

I thought to add decimal numbers using double would be work but it didn't work.. Is there any way to fix this? I would appreciate any tips... thanks...

My english is not that good so if you guys write details i would be appreciated — W.J
– W.J, Commented Mar 25, 2017 at 15:32
change your arraySumBetter method's parameter type to double — Mustafa Çil
– Mustafa Çil, Commented Mar 25, 2017 at 15:35

Murat Karagöz · Accepted Answer · 2017-03-25 15:47:50Z

1

You can not cast from a type to a whole different non related type. With that said double != int. Instead of casting here

   System.out.format("%.1f", (double) arraySumBetter(a));
                               ^ remove

You could change your methods to accept a double[] array as parameter like this

public static double arraySumBetter(double[] a)
  {
    double result = 0;
    for (double value : a)
    {
      result += value;
    }
    return result;
  }

Note that I changed your primitive type from int to double or else you would lose the decimal points.

edited Mar 25, 2017 at 15:47

answered Mar 25, 2017 at 15:35

Murat Karagöz

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2 Comments

Murat Karagöz Over a year ago

@W.J What did you do?

Murat Karagöz Over a year ago

@W.J I changed the return type of arraySumBetter to double I forgot to add that.

Christoph Bimminger · Accepted Answer · 2017-03-25 15:55:19Z

1

use double as IN and OUT in your function.. see my comments

  public static int arraySum(int[] arr)
  {
    int result = 0;
    for (int i = 0; i < arr.length; i++)
    {
      result += arr[i];
    }
    return result;
  }
  public static double arraySumBetter(double [] a) //<<<<<<<<<<<< IN: double, OUT: also double, else the decimals are lost 
  {
    double result = 0; //<<<<<<<<<< here use double, else you loose decimals
    for (double value : a) //<<<<<<<<<<<<<<<<<<<<<<<<<< value is double, because a is double[]
    {
      result += value;
    }
    return result;
  }

  public static void main(String [] args)
  {
    double[] a ={0,2,3,1,0.56};
    System.out.format("%.1f", (double) arraySumBetter(a));
  }

answered Mar 25, 2017 at 15:55

Christoph Bimminger

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2 Comments

W.J Over a year ago

I was thinking of printing out 2 or 3 digits number like 5.55 than how do i do that?

Christoph Bimminger Over a year ago

"%.2f" instead of "%.1f" -> 2 digits

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