Javascript get object from array having min value and min value is needs to find and then find object

Question

I have array of objects in object have different key so i want the object having minimum value in that array

list = [{
    'id': 4,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 1,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 2,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 3,
    'name': 'nitin',
    'group': 'angularjs'
  }
]

I tried by

var minValue = Math.min.apply(Math, list.map(function (o) {
   return o.id;
}))

but it returns only the id not whole object then i have to make more filter for get object

is there any direct method to find object?

Possible duplicate of Compare JavaScript Array of Objects to Get Min / Max — Kapila Perera
– Kapila Perera, Commented Mar 28, 2017 at 7:18

abhishekkannojia · Accepted Answer · 2017-03-28 07:14:24Z

12

You can use Array reduce method:

var list = [
{
'id':4,
'name':'nitin',
'group':'angularjs'
},
{
'id':1,
'name':'nitin',
'group':'angularjs'
},
{
'id':2,
'name':'nitin',
'group':'angularjs'
},
{
'id':3,
'name':'nitin',
'group':'angularjs'
}];

var result = list.reduce(function(res, obj) {
    return (obj.id < res.id) ? obj : res;
});

console.log(result);

answered Mar 28, 2017 at 7:14

abhishekkannojia

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Comments

Weedoze · Accepted Answer · 2017-03-28 07:16:04Z

6

Using Array#reduce()

list = [{
    'id': 4,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 1,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 2,
    'name': 'nitin',
    'group': 'angularjs'
  },
  {
    'id': 3,
    'name': 'nitin',
    'group': 'angularjs'
  }
];

let min = list.reduce((prev, curr) => prev.id < curr.id ? prev : curr);

console.log(min);

answered Mar 28, 2017 at 7:16

Weedoze

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Comments

Vineet Markan · Accepted Answer · 2021-12-30 03:28:19Z

1

I tried these solutions with Array.reduce but none of them were full proof. They do not handle cases where the array is empty or only has 1 element.

Instead this worked for me:

const result = array.reduce(
    (prev, current) =>
      (prev?.id ?? current?.id) >= current?.id ? current : prev,
    null,
  );

It returns null if array is empty and handles other cases well.

answered Dec 30, 2021 at 3:28

Vineet Markan

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Comments

Dax · Accepted Answer · 2017-03-28 07:22:13Z

0

You can check for the object with the lowest id by looping through the array like so, probably not the neatest way, but a solution either way:

var list = [
{
'id':4,
'name':'nitin',
'group':'angularjs'
},
{
'id':1,
'name':'nitin',
'group':'angularjs'
},
{
'id':2,
'name':'nitin',
'group':'angularjs'
},
{
'id':3,
'name':'nitin',
'group':'angularjs'
}]

var tmp = list[0].id;

list.forEach(function (entry) {
    if (entry.id < tmp) {
    tmp = entry;
  }
});

console.log(tmp);

https://jsfiddle.net/camgssk3/

answered Mar 28, 2017 at 7:22

Dax

2032 silver badges7 bronze badges

1 Comment

Kevin K. Over a year ago

there seems to be a typo here, when you initialize tmp var you are pointing to the id not the entity, suggested fix:

var tmp = list[0];  list.forEach(function (entry) {     if (entry.id < tmp.id) {     tmp = entry;   } });  console.log(tmp);

Kudakv · Accepted Answer · 2017-03-28 07:24:39Z

0

other option may be to filter your array as you already have min "id"

var list = [
{
'id':4,
'name':'nitin',
'group':'angularjs'
},
{
'id':1,
'name':'nitin',
'group':'angularjs'
},
{
'id':2,
'name':'nitin',
'group':'angularjs'
},
{
'id':3,
'name':'nitin',
'group':'angularjs'
}];
var min = Math.min.apply(Math, list.map(function (o) {
                return o.id;
            }));
filtered = list.filter(function(elem){
  if(elem.id == min){console.log(elem);return elem;}
})

answered Mar 28, 2017 at 7:24

Kudakv

11 bronze badge

1 Comment

nnnnnn Over a year ago

The question already mentioned filtering the original array based on the result of Math.min(), and explicitly asked for a more direct method.

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