underscore filter array of nested objects

Question

I have the following array of objects:

[{key: "test", values: [{key: "2015-05", values: [{1:2}, {3:4}]}, {}], ...]

I want to filter by the key value to only be left with values after a certain date.

I currently have this, but the resulting the structure is wrong

_.map(temp1, function(value, key) { return _.filter(value.values, function(v) { return v.key > "2015-05"; }); });

"I am using _.map and _.filter but currently stuck." If you show us what you've tried (particularly the _.filter one), we can help you understand what's wrong with what you've done. — T.J. Crowder
– T.J. Crowder, Commented Mar 28, 2017 at 12:20

Community · Accepted Answer · 2017-05-23 11:54:06Z

1

Slight improvement on Frank's answer:

var data = [
  {
    key: "1", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  },
  {
    key: "2", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  }
];

var a = _.map(data, (d) => {
  d.values = _.filter(d.values, (v) => v.key > "2014");
  return d;
});
console.log(a);

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

No need to parse this date format, a string comparison will suffice. Important to note, despite the _.map operation, this will modify the original.

edited May 23, 2017 at 11:54

CommunityBot

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answered Mar 28, 2017 at 13:17

mikeapr4

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Comments

FrankCamara · Accepted Answer · 2017-03-28 12:45:11Z

0

Something like this maybe?

var data = [
  {
    key: "1", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  },
  {
    key: "2", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  }
];

var a = _.map(data, (d) => {
  d.values = _.filter(d.values, (v) => {
    return Date.parse(v.key) > Date.parse("2014");
  });
  return d;
});

edited Mar 28, 2017 at 12:45

answered Mar 28, 2017 at 12:39

FrankCamara

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