Not able to convert image from url into byte array

Question

I am new to android and I need to save image from url into db and fetch it from db. I an converting image from link into byte array but getting the following error:

Cannot Resolve ByteArrayBuffer

This is the code:

 private byte[] getLogoImage(String url){
    try {
             URL imageUrl = new URL(url);
             URLConnection ucon = imageUrl.openConnection();

             InputStream is = ucon.getInputStream();
             BufferedInputStream bis = new BufferedInputStream(is);

             ByteArrayBuffer baf = new ByteArrayBuffer(500);
             int current = 0;
             while ((current = bis.read()) != -1) {
                     baf.append((byte) current);
             }

             return baf.toByteArray();
     } catch (Exception e) {
             Log.d("ImageManager", "Error: " + e.toString());
     }
     return null;
}

Welcome to StackOverflow! Please read the user guidelines on how to ask a good question before posting a question (stackoverflow.com/help/how-to-ask) Thank You — Salman Khakwani
– Salman Khakwani, Commented Mar 31, 2017 at 11:04

Ferdous Ahamed · Accepted Answer · 2017-03-31 12:47:01Z

1

Update your method getLogoImage() as below.

Use AsyncTask and call this method from doInBackground().

Here is the working code. Try this:

private byte[] getLogoImage(String url) {

    try {

        URL imageUrl = new URL(url);
        URLConnection ucon = imageUrl.openConnection();

        InputStream is = ucon.getInputStream();

        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        byte[] buffer = new byte[1024];
        int read = 0;

        while ((read = is.read(buffer, 0, buffer.length)) != -1) {
            baos.write(buffer, 0, read);
        }

        baos.flush();

        return  baos.toByteArray();

    } catch (Exception e) {
        Log.d("ImageManager", "Error: " + e.toString());
    }

    return null;
}

answered Mar 31, 2017 at 12:47

Ferdous Ahamed

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Comments

Nikhil Sharma · Accepted Answer · 2017-03-31 11:12:39Z

0

Try like this

Bitmap bm = null;
   InputStream is = conn.getInputStream();
        BufferedInputStream bis = new BufferedInputStream(is);
        bm = BitmapFactory.decodeStream(bis);
       byte[] imageArray = getBytes(bm);

and after this use below method

  public static byte[] getBytes(Bitmap bitmap) {
    ByteArrayOutputStream stream = new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.PNG, 90, stream);
    return stream.toByteArray();
}

edited Mar 31, 2017 at 11:12

answered Mar 31, 2017 at 11:07

Nikhil Sharma

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3 Comments

greenapps Over a year ago

Pretty bad code to convert the received bytes to a bitmap first. Memory problems. No need to do so as you can put the received bytes directly in a byte array. Or write them to a byte array output stream.

Nikhil Sharma Over a year ago

so can you explain me Mr greenapps how i can do that with explaination

Nikhil Sharma Over a year ago

and suppose if i want to compress my image first thn i want to get byte array how i can do that explain me that also

Rajkumar Kumawat · Accepted Answer · 2017-03-31 11:14:48Z

0

Use This

BitmapFactory.Options options = null;
            options = new BitmapFactory.Options();
            options.inSampleSize = 3;
            Bitmap bitmap = BitmapFactory.decodeFile(url,
                    options);
            ByteArrayOutputStream stream = new ByteArrayOutputStream();

            bitmap.compress(Bitmap.CompressFormat.PNG, 50, stream);
            byte[] byte_arr = stream.toByteArray();

answered Mar 31, 2017 at 11:14

Rajkumar Kumawat

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5 Comments

Dheeraj Singh Over a year ago

getting this error prntscr.com/eqpmom while I am using code as prntscr.com/eqpn24

greenapps Over a year ago

Pretty bad code to convert the received bytes to a bitmap first. Memory problems. No need to do so as you can put the received bytes directly in a byte array. As OP is trying to do. Better help him.

Rajkumar Kumawat Over a year ago

Are u sure file exist inside your device.

Dheeraj Singh Over a year ago

I am getting it from server link

Rajkumar Kumawat Over a year ago

You need to first download the image then convert into byteArray.

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