Javascript, RegEx to split the string to multidimentional array between parentheses

Question

I'm struggling to split the following input string to array:

'((Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25)) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)'.split(/\(([^)]+)\)/g)

Yields:

["", "(Application = smtp AND "Server Port" != 25", " AND ", "Application = smtp AND "Server Port" != 25", ") OR ", "Application = pop3 AND "Server Port" != 110", " OR ", "Application = imap AND "Server Port" != 143", " AND ", "Application = imap OR "Server Port" != 143", ""]

But what I want the result should look like:

["", "(Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25")", OR ", "Application = pop3 AND "Server Port" != 110", " OR ", "Application = imap AND "Server Port" != 143", " AND ", "Application = imap OR "Server Port" != 143", ""]

notice the 1st index "(Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25")"

Any suggestions to achieve this in RegEx?

EDIT Formatted:

I'm having following input string

(
   (
     (App = smtp AND "Server Port" != 25) 
     OR 
     (App = pop3 AND "Server Port" == 20)
   ) 
   AND 
     (App = smtp AND "Server Port" != 35)
 ) 
OR 
(App = pop3 AND "Server Port" != 110) 
AND 
(
   (App = imap AND "Server Port" != 143) 
   OR 
   (App = pop3 AND "Server Port" == 20)
) 
AND (App = imap OR "Server Port" != 143)

wants to transform into:

[
    [
         [
           'App = smtp AND "Server Port" != 25', 
           'OR', 
           'App = pop3 AND "Server Port" == 20'
         ], 
      'AND', 
      'App = smtp AND "Server Port" != 35'
    ], 
   'OR', 
   'App = pop3 AND "Server Port" != 110', 
   'AND', 
   [      
     [
       'App = imap AND "Server Port" != 143', 
       'OR',
       'App = pop3 AND "Server Port" == 20'
     ]
   ], 
   'AND', 
   'App = imap OR "Server Port" != 143'
]

The expected array you gave is not a valid javascript array. — shizhz
– shizhz, Commented Apr 7, 2017 at 5:18
So your expected output is an nested array, I really don't think regex is appropriate tool to archive this, maybe this stackoverflow.com/questions/40477850/… could be helpful for you. — shizhz
– shizhz, Commented Apr 7, 2017 at 5:39

Nishanth Matha · Accepted Answer · 2017-04-07 07:44:31Z

1

As many suggested the better way to do is to create a flattend array. And, deal with each inner array with (split). But, Still for the sake of argument if you want to do it by regex this is one odd / awkward solution to consider:

    var str = '((Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25)) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)';

    var final = str.replace(/\((?!\()/g,"['")        //replace ( with [' if it's not preceded with (
               .replace(/\(/g,"[")               //replace ( with [
               .replace(/\)/g,"']")              //replace ) with '] 
               .replace(/\sAND\s/g,"','AND','")  //replace AND with ','AND','
               .replace(/\sOR\s/g,"','OR','")    //replace OR with ','OR','
               .replace(/'\[/g,"[")              //replace '[ with [
               .replace(/\]'/g,"]")              //replace ]' with ]
               .replace(/"/g,"\\\"")             //escape double quotes
               .replace(/'/g,"\"");              //replace ' with "
    console.log(JSON.parse("["+final+"]"))

answered Apr 7, 2017 at 7:44

Nishanth Matha

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1 Comment

Manjunath Over a year ago

Though its hacky (I will enhance it) its more generic than I expected.

Ibrahim · Accepted Answer · 2017-04-07 06:04:40Z

0

Try this and see if it helps:

\(([^O]+|[^(]+)\)

The complete code will be something like this:

console.log('((Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25)) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)'.split(/\(([^O]+|[^(]+)\)/g))

answered Apr 7, 2017 at 6:04

Ibrahim

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1 Comment

Manjunath Over a year ago

this logic I have already tried but it fails:

'((Application = smtp AND "Server Port" != 25) AND ((Application = smtp AND "Server Port" != 25) OR (Application = smtp AND "Server Port" != 25))) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)'.split(/\(([^O]+|[^(]+)\)/g)

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