I tried to do somthing like that:
$cat1 = array('hello', 'everyone');
$cat = array('bye', 'everyone');
for($index = 0; $index < 2; $index++) {
echo $cat$index[1];
}
It doesn't work of course. What do I need to change here?
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1Why are you not using nested arrays?Ignacio Vazquez-Abrams– Ignacio Vazquez-Abrams2010-12-01 17:40:51 +00:00Commented Dec 1, 2010 at 17:40
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Please go back to your questions and mark the best answer.Jonah– Jonah2010-12-01 17:54:37 +00:00Commented Dec 1, 2010 at 17:54
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1This is one of those examples where one should suggest a better, alternative solution instead of a direct answer.Lotus Notes– Lotus Notes2010-12-01 18:11:07 +00:00Commented Dec 1, 2010 at 18:11
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5 Answers
You should use nested arrays, but this can be done.
$cat1 = array('hello', 'everyone');
$cat2 = array('bye', 'everyone');
for($i = 1; $i <= 2; $i++) {
echo ${'cat' . $i}[1];
}
Reference: http://php.net/language.variables.variable
This would be much better though:
$cats = array(
array('hello', 'everyone'),
array('bye', 'everyone')
);
foreach ($cats as $cat) {
echo $cat[1];
}
Comments
Is this what you intended?
$cat0 = array('hello', 'everyone');
$cat1 = array('bye', 'everyone');
for($index = 0; $index < 2; $index++) {
$varname = 'cat'.$index;
echo $varname[0].' '.$varname[1];
}
Comments
If you insist on doing it this way...
echo ${'cat' . $index}[1];
answered Dec 1, 2010 at 17:44
Ignacio Vazquez-Abrams
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Comments
To echo elements inside arrays, you need to be using
echo $cat[$index]
with your example.
I'm not sure what the $index[1] is supposed to be doing? Maybe I have misunderstood your question.
Comments
You can't reference $index like that, it isn't an array.
echo $cat[$index];
is what you want to do.
