why getting inside PHPdebugger?

Question

Problem started from here. page1.php code snippet:

<a href=page2.php?subid=1>xyz</a>

Nothing related gets logged in php error log. Tried try.. catch block and this seems page1.php works perfectly but gets in trouble while redirecting to page2.php. the javaBridge connection breaks?

PHP notice: Undefined index: start_debug, debug_host, debug_port in PHPdebugger.php
PHP Warning:  fsockopen(): unable to connect to :0

Moreover, PHPdebugger.php is an automatically generated file for JavaBridge (JavaBridge/java/PHPdebugger.php) so there can't be any issue in the file.

try wrapping the href in quotes <a href="page2.php?subid=1">xyz</a> — RiggsFolly
– RiggsFolly, Commented Apr 7, 2017 at 10:47

Sébastien Vanvelthem · Accepted Answer · 2017-04-14 09:43:23Z

0

Looks there's an issue with latest version of the bridge (7.0.1) which enables the PHPDebugger by default. See the mailing list archive: https://sourceforge.net/p/php-java-bridge/mailman/message/35776970/.

Check for newer version or downgrade to 6.2.1.

Alternatively a forked version exists (https://github.com/belgattitude/php-java-bridge/releases) with the PHPDebugger disabled by default. A basic installation can be found here, but will drop support of the Java.inc in favour of the soluble-japha client in coming releases (major version only).

answered Apr 14, 2017 at 9:43

Sébastien Vanvelthem

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