Problems when using setTimeout in setInterval

Question

I want to use setTimeout in setInterval. First time it print out_k:0. After the interval, it prints out_k:1, inside_k:0? I don't understand, I think the inside_k should be 1. The ouside k was 1, its so strange.

     var i = 0;
     var timer = setInterval(function(){
        if(i < arr.length){
            var k=i;
            //console.log("out_i:"+i);
            console.log("out_k:"+k);                
            setTimeout(function(){
                //console.log("inside_i:"+i);
                console.log("inside_k:"+k);
            },500);
            i++;
        }else {
            clearInterval(timer);
        }   
    },500);

what is arr.length?

gurvinder372
– gurvinder372

2017-04-09 14:43:49 +00:00
Commented Apr 9, 2017 at 14:43 — gurvinder372
– gurvinder372, Commented Apr 9, 2017 at 14:43

invernomuto · Accepted Answer · 2017-04-09 15:05:56Z

1

This is the sequence of events during the execution of your code

1) It queued up the first instance of setInterval to be executed after 500ms

2) After 500ms, it queues up second instance of setInterval and executes first instance of setInterval and prints out_k0. It also queues up setTimeout to be executed after 500ms as well when the value of k was still 0.

3) After 500ms, it queues up third instance of setInterval and executes second instance of setInterval and prints out_k1 since value of k is 1 now, but first instance of setTimeout is also executed with inside_k0

and so on.

edited Apr 9, 2017 at 15:05

invernomuto

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answered Apr 9, 2017 at 14:55

gurvinder372

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1 Comment

UTRANANA Over a year ago

You mean setTimeout got the value of k when it queues up?But if I change k to i,it got the the value of i when executed .

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