regex password validation angularjs

Question

I am new to angular js. I have created a login screen. I need to validate my password. it should contain one special character from -'$@£!%*#?&' and at least one letter and number. As of now it accepts all special characters without any limitations. I have following code

if (vm.newpassword_details.password.search("^(?=.*?[A-Za-z])(?=.*?[0-9])(?=.*?[$@£!%*#?&]).{8,}$")) {
  var msg = "Password should contain one special character from -'$@£!%*#?&' and at least one letter and number";
  alert(msg);
}

Do you mean you want to limit the chars a user can use for a password? It is not best practice. You can achieve it with /^(?=.*?[A-Za-z])(?=.*?[0-9])(?=.*?[$@£!%*#?&])[A-Za-z0-9$@£!%*#?&]{8,}$/ regex. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Apr 12, 2017 at 10:41

Wiktor Stribiżew · Accepted Answer · 2017-04-12 11:32:17Z

2

Note that your current regex imposes 4 types of restriction:

At least one ASCII letter ((?=.*?[A-Za-z])),
At least one digit ((?=.*?[0-9])),
At least one specific char from the set ((?=.*?[$@£!%*#?&]))
The whole string should have at least 8 chars (.{8,})

The . in .{8,} can match any char other than line break chars.

If you plan to restrict the . and only allow users to type the chars from your sets, create a superset from them and use it with RegExp#test:

if (!/^(?=.*?[A-Za-z])(?=.*?[0-9])(?=.*?[$@£!%*#?&])[A-Za-z0-9$@£!%*#?&]{8,}$/.test(vm.newpassword_details.password)) {  /* Error ! */  }

See the regex demo

answered Apr 12, 2017 at 11:32

Wiktor Stribiżew

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