How to split a Elements in scala into a Array of Strings

Question

I have some troubles into slitting an Element (scraped from the web) into an Array of Strings.

Here is my code :

link = "http://www.myurl.com"
val doc: Document = Jsoup.connect(link).get()
val title2 = doc.select("li > h3 > a").toString

that give me :

<a href="/association/129033/69-1ere-compagnie-d-arc-du-dauphine.htm">1ERE COMPAGNIE D'ARC DU DAUPHINÉ</a>
<a href="/association/129512/69-38sms.htm">38SMS</a>
<a href="/association/128940/69-40-batteurs.htm">40 BATTEURS</a>
<a href="/association/129543/69-4l-four-liberty.htm">4L FOUR LIBERTY</a>
<a href="/association/129820/69-a-bord-perdu.htm">A BORD PERDU</a>

what i want is to have only the href in a Array of Strings. Only take the strings in the " ".

I've try to use JavaConverters like asScala, but i'm falling working with it :/

Thanks

pezetem · Accepted Answer · 2017-04-13 08:56:22Z

1

simply extract href attributes from the a you get like:

doc.select("li > h3 > a").map(link -> link.attr("href")).toArray

take a look the more attribute extracting features from Jsoup

edited Apr 13, 2017 at 8:56

answered Apr 13, 2017 at 8:50

pezetem

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2 Comments

Leo Tripot Over a year ago

did you mean : doc.select("li > h3 > a").map(doc -> doc.attr("href")).toArray ? also map make an error (map not a member of org.jsoup.Elements)

pezetem Over a year ago

i do not have how to test it but try this -> doc.select("li > h3 > a").asScala.map(doc -> doc.attr("href")).toArray . Let me know it it helps

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