How to add an array (double) as a field to a struct variable?

Question

I have a structure variable and want to add a field and fill the row with the values of an array (double). The following code works but isn't very nice. Is there a more elegant way to add a field including values without the use of the mat2cell function or a for loop?

field1 = 1:10
field2 = 4:13
%create struct with field 'start' with 10 values
A = struct('start',mat2cell(field1,1,ones(1,numel(field1))))
%transform field2 to cell 
temp = mat2cell(field2,1,ones([numel(field2),1]));
%add field 'end' with 10 values
[A(1:numel(field2)).end] = temp{:};

Suever · Accepted Answer · 2017-04-13 17:58:42Z

2

You can use num2cell rather than mat2cell which will (by default) place each element in it's own cell. Unfortunately, you will still need a temporary variable.

A = struct('start', num2cell(field1));
tmp = num2cell(field2);
[A.end] = tmp{:};

answered Apr 13, 2017 at 17:58

Suever

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Mendi Barel · Accepted Answer · 2017-04-13 18:41:34Z

1

Download "catstruct": https://www.mathworks.com/matlabcentral/fileexchange/7842-catstruct

clear
field1 = 1:10;
field2 = 4:13;
A = struct('start',num2cell(field1));
A = catstruct(A, struct('end',num2cell(field2)));

For performance you better use single field that contain array:

clear
field1 = 1:10;
field2 = 4:13;
A=[];
A.start = field1;
A.end = field2;

edited Apr 13, 2017 at 18:41

answered Apr 13, 2017 at 18:27

Mendi Barel

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