PHP type hinting array of objects

What would be the best way to check the type of an array in PHP?

Lets say I have the following:

class Toggler
{

    protected $devices;

    public function __construct(array $devices)
    {
        $this->devices = $devices;
    }

    public function toggleAll()
    {
        foreach ($this->devices as $device)
        {
            $device->toggle();
        }
    }

}

What happens here is simple: The Toggler class requires an array of 'Devices', loops over those devices and calls the toggle() method on them.

What I want however, is that the array of devices must contain only objects that implement the Toggleable interface (which would tell the object to supply a toggle() method).

Now I can't do something like this, right?

class Toggler
{

    protected $devices;

    public function __construct(Toggleable $devices)
    {
        $this->devices = $devices;
    }

    public function toggleAll()
    {
        foreach ($this->devices as $device)
        {
            $device->toggle();
        }
    }

}

As far as I know you can't typehint an array as an array in PHP has no type (unlike languages like C++).

Would you instead have to check type in the loop for each device? And throw an exception? What would be the best thing to do?

class Toggler
{

    protected $devices;

    public function __construct(array $devices)
    {
        $this->devices = $devices;
    }

    public function toggleAll()
    {
        foreach ($this->devices as $device)
        {
            if (! $device instanceof Toggleable) {
                throw new \Exception(get_class($device) . ' is not does implement the Toggleable interface.');
            }

            $device->toggle();
        }
    }

}

Is there a better, cleaner, way to do this? I figured as I was writing this pseudo code you would also need to check if the device is an object at all (else you can't do get_class($device)).

Any help would be appreciated.