Open SAP with Python GUI Script win32com.client.Dispatch("Sapgui.ScriptingCtrl.1")

Question

I made a script to open SAP GUI with Python.

from win32com.client import Dispatch
#reference sapfewse.ocx like a dll file with makepy()
app = win32com.client.Dispatch("Sapgui.ScriptingCtrl.1")
conn = app.OpenConnection("System_Name", True)
ses = conn.Children

I am able to open the SAP GUI Scripting window with the code but, I think there is a problem with the Children(0) part as it does not allow me to use the ses.FindByID to access the ID tags.

Any tips?

sys.argv = ["makepy", r"C:\Program Files (x86)\SAP\FrontEnd\SAPgui\sapfewse.ocx"] makepy.main() — maseyh
– maseyh, Commented Apr 18, 2017 at 12:44

Jesus Perez · Accepted Answer · 2020-09-11 17:12:39Z

1

I believe for some reason makepy doesn't resolve the inheritance of the classes in the SAP dll correctly. You have to make sure you clean out your gencache of any files generated for the SAP dll, then dispatch the Sapgui.ScriptingCtrl.1 dynamically.

import win32com.client as win32

app = win32.dynamic.Dispatch("Sapgui.ScriptingCtrl.1")

answered Sep 11, 2020 at 17:12

Jesus Perez

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