I am a beginner of Java. I know how to print a reversed array but I don't know how to print half of it. For example:
Original Array A = {1,2,3,4,5,6,7,8,9,0}
After the function:
Transformed Array A' = {1,2,3,4,5,0,9,8,7,6}
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3 Answers
private void reverse(int[] ar, int i, int j) {
if(i>j)
return;
else{
int temp = ar[i];
ar[i] = ar[j];
ar[j] = temp;
reverse(ar, ++i, --j);
}
}
Call reverse(ar, (ar.length/2), ar.length-1) from the main method.
1 Comment
Laser Infinite
I thought your code would be useful but I got an ArrayIndexOutOfBoundsException when I used your code so what is going on?
Try the following steps,
- Find the length of the array - N
- Create another array of size - N
- Find the Half - n
- Copy first n elements
- Break, start from last(index to the last element) and copy the elements til nth location (Note index pointer should be decremented)
Comments
Please find the perfect solution guys!!!
import Arrays & Scanner packages
public static void main(String[] args) {
Scanner size = new Scanner(System.in);
System.out.println("Enter Array Size : ");
int arraySize = size.nextInt();
Scanner data = new Scanner(System.in);
System.out.println("Enter Array Data : ");
int arrayData[] = new int[arraySize];
for(int inputLoop = 0; inputLoop < arraySize; inputLoop++) {
arrayData[inputLoop] = data.nextInt();
}
System.out.println("Original Array : " + Arrays.toString(arrayData));
int centerPoint = arrayData.length / 2;
int endPoint = arrayData.length - 1;
reverse(arrayData, centerPoint, endPoint);
System.out.println("Transformed Array : " + Arrays.toString(arrayData));
data.close();
size.close();
}
private static void reverse(int[] arrayData, int centerPoint, int endPoint) {
if(centerPoint > endPoint || centerPoint == endPoint) {
return;
}
else {
arrayData[centerPoint] = arrayData[centerPoint] - arrayData[endPoint];
arrayData[endPoint] = arrayData[centerPoint] + arrayData[endPoint];
arrayData[centerPoint] = arrayData[endPoint] - arrayData[centerPoint];
reverse(arrayData, ++centerPoint, --endPoint);
}
}
}
