Php mysql to json output formatting

Question

I have my json echo working

echo '{"detailsjson":'.json_encode($var).'}';

Now I want to write this to a file on server example output.json

I use the php code

 $json_data = {"detailsjson":.json_encode($var).};
 file_put_contents('output.json', $json_data);

i don't get the file, but for

file_put_contents("output.json", json_encode($var));

it work. I want to include detailsjson in my json so that i can get

{"detailsjson":[{"Name":"Amateur : Paul Smith",.....

Thanks

add echo $json_data; before writing to file

splash58
– splash58

2017-04-23 06:45:27 +00:00
Commented Apr 23, 2017 at 6:45 — splash58
– splash58, Commented Apr 23, 2017 at 6:45

Community · Accepted Answer · 2017-05-23 12:02:29Z

2

Your $json_data variable is not "valid". You have to put everything in single quotes to make it work (not in double quotes because you use them in your json). Like this:

$json_data = '{"detailsjson":'.json_encode($var).'}';

Update (see comment from Hassan):
It is better to do this with pure arrays.

$json_data = json_encode(['detailsjson' => $var]);

You can compare them by speed here (using a string) and here (using pure arrays).

edited May 23, 2017 at 12:02

CommunityBot

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answered Apr 23, 2017 at 6:45

Tom Udding

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1 Comment

hassan Over a year ago

also it will be better to deal with pure arrays then encode your whole final array, $array = json_encode(['detailsjson' => $var]);

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