myArray = []
textFile = open("file.txt")
lines = textFile.readlines()
for line in lines:
myArray.append(line.split(" "))
print (myArray)
This code outputs
[['a\n'], ['b\n'], ['c\n'], ['d']]
What would I need to do to make it output
a, b, c, d
You're adding a list to your result (split returns a list). Moreover, specifying "space" for split character isn't the best choice, because it doesn't remove linefeed, carriage return, double spaces which create an empty element.
You could do this using a list comprehension, splitting the items without argument (so the \n naturally goes away)
with open("file.txt") as lines:
myArray = [x for line in lines for x in line.split()]
(note the with block so file is closed as soon as exited, and the double loop to "flatten" the list of lists into a single list: can handle more than 1 element in a line)
then, either you print the representation of the array
print (myArray)
to get:
['a', 'b', 'c', 'd']
or you generate a joined string using comma+space
print(", ".join(myArray))
result:
a, b, c, d
You could do the following:
myArray = [[v.strip() for v in x] for x in myArray]
This will remove all the formatting characters.
If you do not want each character to be in its own array, you could then do:
myArray = [v[0] for v in myArray]
To print, then 'print(', '.join(myArray))
It seems you should be using strip() (trim whitespace) rather than split() (which generates a list of chunks of string.
myArray.append(line.strip())
Then 'print(myArray)' will generate:
['a', 'b', 'c', 'd']
To print 'a, b, c, d' you can use join():
print(', '.join(myArray))
You can try something like:
import re
arr = [['a\n'], ['b\n'], ['c\n'], ['d']]
arr = ( ", ".join( repr(e) for e in arr ))
arr = arr.replace('\\n', '')
new = re.sub(r'[^a-zA-Z0-9,]+', '', arr)
print(new)
Result:
a,b,c,d
