How to get the true dimension of a numpy array in python?

Question

I try to display a numpy file, then display its correct length, I put my file in folder:

import numpy as np
import os
path= "C:\\Users\\user\\Folder"
files= os.listdir(path)
filepath= os.path.join(path, files[0])
file0= np.load(filepath)
print(file0)
print (len(file0))

The result is an imbrication of tables, which gives me as length=1 instead of length=8000 :

[[ 0.01437869  0.01506449  0.01579909 ...,  0.04166172  0.0417285
   0.04172079]]

1

But I need to have is:

[ 0.01437869  0.01506449  0.01579909 ...,  0.04166172  0.0417285
   0.04172079]

8000

How to resolve this problem please.

Use .ravel() or np.squeeze().

Divakar
– Divakar

2017-04-27 09:50:34 +00:00
Commented Apr 27, 2017 at 9:50 — Divakar
– Divakar, Commented Apr 27, 2017 at 9:50
and have a look at .shape instead of len().

Nils Werner
– Nils Werner

2017-04-27 09:52:46 +00:00
Commented Apr 27, 2017 at 9:52 — Nils Werner
– Nils Werner, Commented Apr 27, 2017 at 9:52
Looks like the true file0.shape is (1,8000).

hpaulj
– hpaulj

2017-04-27 12:33:26 +00:00
Commented Apr 27, 2017 at 12:33 — hpaulj
– hpaulj, Commented Apr 27, 2017 at 12:33

Trolldejo · Accepted Answer · 2017-04-27 09:54:48Z

3

This should work:

file0= np.load(filepath)[0]

answered Apr 27, 2017 at 9:54

Trolldejo

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1 Comment

Jaime Over a year ago

I like this syntax to unpack single item sequences better, but YMMV: file0, = np.load(filepath).

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