Generic Linked List in java

The E here private class Node<E> { hides the E here :public class LinkedList<E> {

The Node class doesn't need to be generics. It contains a generics field value that depends on the E generics from LinkedList. It is enough.

public class LinkedList<E> {
    private Node head = null;

    private class Node {
        E value;
        Node next;

        // Node constructor links the node as a new head
        Node(E value) {
            this.value = value;
            this.next = head;//Getting error here
            head = this;//Getting error here
        }
    }

    public void add(E e) {
        new Node(e);
    }

    public void dump() {
        for (Node n = head; n != null; n = n.next)
            System.out.print(n.value + " ");
    }

    public static void main(String[] args) {
        LinkedList<String> list = new LinkedList<String>();
        list.add("world");
        list.add("Hello");
        list.dump();
    }
}

EDIT

could you please tell me what compiler wants to say when it throw error message

When you write :

 this.next = head;

you have to be aware that these two variables don't rely on the same type.

• next is a field declared in Node<E> class in this way : Node<E> next

• head is a field declared in LinkedList<E> class in this way : Node<E> head

But the E type declared in the Node<E> class is not considered by the compiler as being the same E type declared in the LinkedList<E> class because these are two distinct type declarations.

So here :

this.next = head;

the compiler cannot assign from LinkedList<E>.Node<E> to LinkedList<E>.Node<E> because the Node<E> next field from the Node<E>class and the Node<E> head field from the LinkedList<E>class don't declare the same type (and are not convertible either).