PHP/HTML Input Type Number

Question

is there any way I can get the iterate through a lot of input type number's and only print out the values that have a value greater than 0?

Let's say I have 10

        <form action="displayInfo.php" method="post">


    <table cellpadding="6">
      <tr>
        <th>Description</th>
        <th>Price</th>
        <th>Weight</th>
        <th>Image</th> 
        <th>Quantity</th>
      </tr>
    <!-- PHP LANGUAGE -->
    <?PHP
        $sql = "SELECT * FROM parts";
        $q = $conn->query($sql) or die("ERROR: " . implode(":", $conn->errorIndo()));

        while( $row = $q->fetch(PDO::FETCH_ASSOC))
        {

            echo '<tr>' .
                '<td>' . $row['description'] . '</td>' .
                '<td>' . $row['price'] . '</td>' .
                '<td>' . $row['weight'] . '</td>' . 
                '<td> <img src="' . $row[pictureURL] .'" alt="' . $row[number] . '" style="width:50px;height:50px;">' .
                '<td> <input type="number" name = "' . $row[number] ." id= "'. $row[number] . '"  value="0">' .
                '</td>' . '</tr>';
        }
        echo "</table>";

    ?> 
    </table> <br>



    <input type="button" id="submit" value="Submit" />
    </form>

So they are dynamically created with an id that have values 1,2,3,...10. The values are then updated through user input.

Is there anyway I can catch the data passed by the submit button for the values entered by the user that are greater than 0? If so, how would I also pass the description or even the $row[number] along with the value that is associated with it. the id of the input type number = the $row[number] as displayed in the code.

Just for display purposes so the input type has a value stored in it. So it shows the user that a number would Ideally go into the cell. — osinp
– osinp, Commented May 2, 2017 at 8:21
To begin with, form controls that do not have a name attribute are not even sent to the server. — Álvaro González
– Álvaro González, Commented May 2, 2017 at 8:30
Apologies I accidentally forgot I have an id and a name attribute. — osinp
– osinp, Commented May 2, 2017 at 8:48
Stop outputting die statements on SQL failure, this will disrupt user experience and will output dangerous error details to potential hackers. — Mm-Art-In
– Mm-Art-In, Commented May 2, 2017 at 8:55

Álvaro González · Accepted Answer · 2017-05-02 10:24:44Z

3

The simplest way is probably to use a PHP feature, explained at How do I create arrays in a HTML <form>?

In short, you rename the form controls to use a common prefix, add square brackets to make PHP convert them into array and then loop data as any other array:

'<td> <input type="number" name = "row[' . $row[number] . ']" id= "'. $row[number] . '"  value="0">' .

I've also fixed a missing quote but I presume it isn't in your actual code.

Then:

foreach ($_POST['row'] as $number => $value) {
}

And since it's an array you can use the usual goodies, e.g.:

$rows = array_filter($_POST['row'], function($val){
    return is_numeric($val) && $val>10;
});

Demo

edited May 2, 2017 at 10:24

answered May 2, 2017 at 8:58

Álvaro González

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2 Comments

osinp Over a year ago

If I may ask, the code under your "Then:" would be in the file that the form goes to, but what from what I gather you are getting the row array that was passed and you are using the number that would be in the array and setting it equal to a new variable called value. Now you create a new variable called rows and go through the array row by creating a function with the passed in variable val which returns val if it is a number and is greater than 10. Is $val supposed to be $value? Thank you for helping. I'm still a beginner so I'm just trying to understand what exactly is going on.

Álvaro González Over a year ago

They're independent suggestions, you don't possibly need to do both. foreach is a PHP flow control structure, you can read about it in the manual. Also, make sure you understand what arrays are.

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