Remove values using condition from multidimensional array using java-script

Question

I have a multidimensional array as following.

[['Base: Values','55','98','90.8'],['Value First','55','98','90.8'],['Top','55','98','90.8'],['Bottom','55','98','90.8']]

I want to remove entire values if it includes 'Top' or 'Bottom', so that i will get a result like this:

[['Base: Values','55','98','90.8'],['Value First','55','98','90.8']]

Somebody give me a solution please. Thanks in advance.

Coldiary · Accepted Answer · 2017-05-03 08:09:38Z

1

You can filter the array, providing a function to determine if an element should be included or not :

array.filter(e => !e.includes('Top') && !e.includes('Bottom'));

Example:

const data = [
    ['Base: Values','55','98','90.8'],
    ['Value First','55','98','90.8'],
    ['Top','55','98','90.8'],
    ['Bottom','55','98','90.8']
]
const filtered = data.filter(e => !e.includes('Top') && !e.includes('Bottom'));
console.log(filtered)
console.log(data)

EDIT: To exclude if any string in array values contains a specific part, you could change the predicate to check if at least one string contains the part:

array.filter(e => !e.some(i => i.includes('part to find')));

Example:

const data = [
    ['Base: Values','55','98','90.8'],
    ['Value First','55','98','90.8'],
    ['Top','55','98','90.8'],
    ['Bottom','55','98','90.8']
]
const filtered = data.filter(e => !e.some(i => i.includes('Value')));
console.log(filtered)
console.log(data)

edited May 3, 2017 at 8:09

answered May 3, 2017 at 6:55

Coldiary

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1 Comment

Amit Over a year ago

Thanks for your answer. Its working fine if i am checking exact word. What i have to do to remove by checking a portion only. In the above example if i want to delete ['Base: Values','55','98','90.8'] by checking 'Base ' only??

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