Regex find the string after the integer

Question

I am trying to find the string after the integers in a field but seem to get stuck on the strings part.

Pattern intsOnly = Pattern.compile("\d+");

1000 Stack Overflow ?                      1000 Java Developer Way
                                           1000 Spring Developer Avenue
                                           1000 Stack Overflow Road (this requested)

2000 String  ?                             2000 Integer Creek Way
                                           2000 Float Street
                                           2000 Double Trail
                                           2000 String Way (this requested)

The regex I have here pulls in all the 1000 and 2000 address number records from the field while I need to match at least the first string after the integers.

Requested:

1000 Stack Overflow Road
2000 String Way

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. — Ousmane D.
– Ousmane D., Commented May 4, 2017 at 14:58
Could just do (\d+) ([a-zA-Z]+) and get the second group that matches — austin wernli
– austin wernli, Commented May 4, 2017 at 15:00

Sezin Karli · Accepted Answer · 2017-05-04 14:58:29Z

1

You can define the string part as a group and fetch it like this:

Pattern.compile("\d+ ([a-zA-Z ]+)");

answered May 4, 2017 at 14:58

Sezin Karli

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Community · Accepted Answer · 2020-06-20 09:12:55Z

0

You can get it with this regex: \d+\s([ \w]+)

Demo on Regex101

edited Jun 20, 2020 at 9:12

CommunityBot

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answered May 4, 2017 at 15:06

Mistalis

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